No idea. I couldn't find the sequence in the OP at http://www.research.att.com/~njas/sequences but swapping the commas for spaces they all...
The reason for the zeroes is that you keep overflowing the end of the arrays. You aren't guaranteed anything about random numbers, that's the...
Try GetAsyncKeyState().
6121
Please use code blocks when posting code; it makes code much easier to read. Looking through it though, it seems mostly OK. What does the...
float f=(num & 0xff) + float(dec & 0xff)/100.0;
I'd probably use an array of 26 ints initialised to zero, then for each letter encountered increment the relevant element. Pseudocode: int...
Yeah I got that. I can't believe you think members of the f(x)=Nx family are discontinuous. Remember, N is an integer, but x isn't; x is valid...
(14) Why? Ans: Why not?
Yes, I know x is a variable. What's the problem with observing that at some point in the graph, x=N? After all, if a function is valid for -Inf...
X | d------------c------Y | / | | / | |/ | P----------------W--------- bisecting line of aPd |\...
Well, mayjune gave you one, you can come up with others; here are a few: * ** *** **** * * * * * * * * * *** *** *** ***...
The length depends on the instruction and you can find that info in the processor data sheet. I think pointers are 2 bytes; this goes back a long...
Okidoki, if you want WolframAlpha quotes, try this one:...
> So, as you restrict the values to integers, you are basically making the func discontinuous. No, I restrict N to integers but not x, and this...
Would it help to point out that my original intent behind "f(x)=x+x+x...(x times)" was to describe a family of straight lines rather than a single...
Don't take it personally. We get a lot around here who are lazy, they think we're expert enough to do their homework for them but not expert...
Well how else do I interpret And you definitely called me crazy more than once. So I too see little point in continuing. You won't listen...
You just can't help with the personal remarks can you? Calling me a fool isn't exactly polite. I haven't contradicted myself once. I keep...
>So, how the hell does you graph become continuous, man ??? That shows your incompetence in maths. f(x)=x is continuous for all x. f(x)=x+x...
Separate names with a comma.
