Nope, that's where you go wrong. f'(x) = x as long as N is a number independent of x. When N is independent of x, f'(x) = N. See, f(x) = x + x +...
Yeah .. as long as N is a number like 2, 3 -9, 11.2 or any number ... f'(x) = N.
Yeah. f(x) = 5x => f'(x) = 5 = x. So ???
Or, if you consider f(x) = x + x + x + x + x i.e. 5x then ... (1) Yes (2) Yes because f'(x) = 5 which is independent of x.
What is f(x) ? If f(x) = x + x + .. (x times).. + x, then answer would be -- (1) No (2) No Explanation : (1) For all x, f'(x) would not be some...
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