Sorry friend, in TurboC output of this code is 24 6 Here the simple reason, parenthesis work first and value of a incremented by 1 then...
#include <stdio.h> int main() { int x[] = {10,20,30,40, 50}; int *y; y= x;...
What is incremented by these oparators...address or value?? Plz come with explanation. ++(*y).....value/address? *++y.....value/address?...
I change the example a little. Now the o/p is j=2 *p=5 here the statement act like j= --*p and p++. why? if the actual increment or decrement of...
but as per operator precedence in c, ++ should evaluate first than =. please explanation?
expression1 ? expression2 : expression3 if expression1 satisfied(i.e. nonzero) then only expression2 will return, otherwise expression3 will...
what the exact value(non-zero) returned by printf()....?
Actually I am asked "How a C programe can be write without semicolon?" I think it indicates any processes by which we can capable to code any C...
What the Non-Zero value printf() returns ??
Write a C program without any semicollon (;)..:D
its not clear to me....please explain
anyone can explain me...How printf() function works. there any way to find out the coding of any library function in Turbo C??
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