trying to calculate the number of letters in a string

Discussion in 'C' started by travelmate81, Nov 23, 2007.

  1. travelmate81

    travelmate81 New Member

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    hello people....i just started to learn C so im very new with it....
    im trying to calculate to the number of letters that i have in a string
    for example :
    string = GoforEEeexpeRT
    the result should be
    the letter is E , 5 times.

    so far i tried to this but im getting error when im trying to run it .
    can someone help me with it, thanks in advance.

    Code:
    #include <stdio.h>
    #define ABC 100
    int main()
    {
    	char st[ABC];
    	int a[ABC], i,j;
    	
    	printf("\nPlease enter the string\n");	
    	for (i=0; i<ABC; i++)	 /* initialization */
    		a[i]=0;	
    	
    	j=0;
        while (st[j]!='\0')
    	{
    		if (st[j]>='A'&& st[j]<='Z')
    			st[j]=st[j]+32 ;
    		j++;
    
    	}
    		i=0; 
    		for(i=0;i<ABC;i++)
    			for(k=i;k<ABC;k++)
    			{
    				if (st[k]==st[i])
    					a[i]++;
    			}
    
    		while(
    				i++;
    		ch[i] = s[i];
    		printf("the letter is %s\n", s);
    	}
    }
     
    Last edited by a moderator: Nov 24, 2007
  2. Titus2go

    Titus2go New Member

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    Hi travelmate81,

    Here is just a short solution to your problem.

    Code:
    #include <stdio.h>
    #include <ctype.h>
    
    #define SLENGTH 14
    
    int count_occurrence(char word[], char letter);
    
    main()
    {
    	int i, count;
    	char word[SLENGTH], code;
    	printf("Please enter a string: ");
    	//read characters and put them into the array
    	for(i = 0; i < SLENGTH; i++)
    	{
    		scanf("%c", &word[i]);
    		//turn all the characters in word to lower case
    		word[i] = tolower(word[i]);
    	}
    	//count the occurrence of each letter
    	for(code='a';code<='z';code = code+1)
    	{
    		count = count_occurrence(word, code, SLENGTH);
    	    if(count != 0)
    			printf("The letter %c appeared %d times\n", code, count);
    	}
    }
    
    int count_occurrence(char word[], char letter, int length)
    {
    	int i, count = 0;
    	for(i = 0; i < length; i++)
    		if(word[i] == letter)
    			count++;
    	return count;
    }
    I hope this helps, you can modify it if you want.
     
  3. shabbir

    shabbir Administrator Staff Member

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    Your program has an error. You have not defined the program correctly.

    Here is the program to count all the strings in an array
    Code:
    #define SLENGTH 26
    
    int main()
    {
    	int i;
    	char word[SLENGTH];
    	int count[SLENGTH] = {0};
    	printf("Please enter a string: ");
    
    	scanf("%s", word);
    	for(i = 0; i < SLENGTH && word[i] != '\0'; i++)
    	{
    		word[i] = tolower(word[i]);
    		count[word[i]-'a']++;
    	}
    	for(i = 0; i < SLENGTH; i++)
    	{
    	    if(count[i] != 0)
    			printf("The letter %c appeared %d times\n", i+'a', count[i]);
    	}
    	getch();
    }
    
     

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