can someone solve my problem if the string is college the output must be c=1 o=1 l=2 e=2 g=1 it counts that how many a letter does it used thnk you ^^
I'd probably use an array of 26 ints initialised to zero, then for each letter encountered increment the relevant element. Pseudocode: Code: int arr[26] initialise to zero char *str="college" for each character c in str arr[str[c]-'a']++ end for for each element e of arr if non-zero print the letter (e+'a') and the count end if end for arr[str[c]-'a']++ is the clever bit: str[c] is a char between 'a' and 'z', and subtracting 'a' from that gives us a number from 0-25 which we use as the index into the array. It may be a good idea to add some limits checking to this, for example if (str[c]>='a' && str[c]<='z') so that you don't accidentally increment something not in the array.
