Basiclly what im trying to to (and not for uni but for someone else) is to try and create a function to take a interger from a user and find the factorial of is. Factorial being : The factorial of 2 is: 2x1=2 The factorial of 9 is: 9 x 8x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 720 So far i can do: int num; count<< "Please enter a interger.."; cin<< num; now i need the funcation to somehow do the factoril bit :P this being a error trap saying if the answer is <=0 then jsut return 0 if(numfac==>0) { cout>>numfac; else cout<<0; } So if anyone can help in being able to do the function bit that would be amazingly helpfull thanks sexy people (ignore any mistakes i just that bit on the spot lol)

Write a function that calculates the given number multiplied by that number minus one. Ensure for 1 and less it returns a suitable value. Make sure it is fully debugged before you go on to the next step and that some test values return the correct result, e.g. 1->1, 3->6, 6->30, 12->132 (remember at this point all it is calculating is n*(n-1). Then instead of "that number minus one", just call the function from within itself with "that number minus one" as the given number. Easy! Code: int f(int n) { ... // recursive call int something=someval*f(n-1); ... return what? }

Code: //Aim: to Find Factorial Of a No. Using function [COLOR="Blue"]#include<iostream.h> #include<conio.h>[/COLOR] [COLOR="Red"]long int fact(int);[/COLOR] void main() { int n; long int f=1; clrscr(); cout<<"\n enetr a value:"; cin>>n; f=fact(n); cout<<"\n the factorial is:"<<f; getch(); } [COLOR="red"]long int fact(int m)[/COLOR] { int i; long int f=1; for(i=1;i<=m;i++) { f=f*i; } return(f); }

And did you feel the need to inform the entire Tour de France team when you finally stopped falling off your bike?