Hi, Iam using Apache Tomcat 5.5.20. Iam trying to deploy a web application named "ShowLifecycles".It has one JSP file named "ShowLifecycles.jsp" and a .Class file named "MyAppListener.class". I have packaged them as follows: 1)<TOMCAT-ROOT>/webapps/ShowLifecycles/ShowLifecycles.jsp 2)<TOMCAT-ROOT>/webapps/ShowLifecycles/WEB- INF/classes/examples/MyAppListener.class My web.xml looks like this: <?xml version="1.0" encoding="ISO-8859-1" ?> <web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4"> <display-name>ShowLifecycles</display-name> <description>An example of how to use lifecycle events</description> <listener> <listener-class> examples.MyAppListener </listener-class> </listener> </web-app> When I point my browser to http://localhost:8080/ShowLifecycles/ShowLifecycles.jsp it tells "The requested resource(/ShowLifecycles/ShowLifecycles.jsp) is not available". MyAppListener implements a ServletContextListener.I have typed the URL in correct case. Another Web application of a similar type was able to execute a JSP file in it. I have tried using <jsp-file> and <servlet-mapping> in web.xml. Still it doesn't work. I would be grateful to receive a prompt reply.
WAR stands for Web ARchive, export your project as WAR file from the IDE you are using for development, and then use the Tomact Manager to deploy the WAR file.