i have some doubts regarding bash scripting , 1) i need to display permission of a given file in the following format : Owner : Read Write Group : Read Write Others : Read Execute so i wrote this code : Code: echo -n "Enter Filename : " ; read fname ; # check if file exists if [ -e $fname ] then #display fap for owner echo "Owner" ls -l $fname|awk '{print $1 }' |tee temp | cut -c2-4 #display fap for group users echo "Group" cat temp | cut -c5-7 #display fap for other users echo "Other" cat temp | cut -c8-10 else echo "FIle does not exist" fi the output i get is : Code: Owner rwx Group r-x Others r-- i want to print the words "Read" "Write" "Execute" instead of 'rwx'. If it were only for the owner , i could use the test command and -r, -w, -x options but that doesnt work for Group and Other users, how do i do that ? 2) i need to delete all duplicate files , so i wrote this, Code: find . -maxdepth 1 -type f -print0 | xargs -0 md5sum | sort | uniq -w 32 -c | awk '{ print $1, $3 }' | find -ok rm {} \; but it is incomplete, it deletes all files , which means even the original file would be lost. 3) Need to check if any user has logged-in more than once in different terminal, then display the no. of instances of that login. Sorry , no code tried for this one. I dont know where to start from. 4) And im trying to display files that have been created today , as i understand , unix keeps the track of files by the modification date and doesn't store the creation date, so how do i accomplish this task. i have tried my best to solve these doubts by reading numerous tutorials . but still couldn't find my answers. Please help. Thanks for reading the post.