a few questions about C++ source code

Discussion in 'C++' started by mac1234mac, Sep 26, 2008.

  1. mac1234mac

    mac1234mac New Member

    Sep 25, 2008
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    I have before my eyes source code, but I Can't understand certain parts of

    1. #pragma - what does it mean, is it some directive for precompilator?.
    for example: what does it mean - #pragma resource "*.dfm;" or
    or #pragma package (smart_init);?.
    2. what does word __fastcall mean in expression
    int __fastcall ABC:SetABC() {};
    3. what does expression: k = 1 << i; mean?.
    4. what is the effect of running following line of text:
    SignalForm->CheckBox20->Enabled = (maskIO & 0x08) ? true :
    I particularly mean expression in parenthesis: (maskIO & 0x08) what
    does it mean?.
    Shouldn't there be applied bit conjunction operator?.

    Thank You for answer.
  2. oogabooga

    oogabooga New Member

    Jan 9, 2008
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    #pragma is a preprocessor directive that speaks directly to the implementation,
    such as the compiler or linker, or possibly the IDE. Check your documentation.

    __fastcall is a suggestion to use registers to pass arguments, if possible, instead
    of using the stack.

    1 << i is 1 shifted i times leftwards. It is equal to 2 to the power of i.

    (maskIO & 0x08) is masking bit 3 (2 to the power of 3 is 8).
    If bit 3 is set, the result is non-zero (true).

    I do not know what a "bit conjunction operator" is (unless it is just &).

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