print the letter "S"

hi.
i need to print the letter "S"
in the following format.
it should have 15 rows and 18 columns.
i have to do it using "for.." and "if.." statements

Code:

****************
**------------**
******--------**
****
****
****
****--------****
-----------*****
-----------*****
            ****
            ****
            ****
****--------****
***----------***
**-----------***

 

Try this code hope it works...

Code:

#include<stdio.h>
#include<conio.h>
void main()
{
int a[15][3],i,j;
clrscr();
for (i=0;i<3;i++)
{
for(j=0;j<16;j++)
{
printf("%d",a[i][j]=0);
}
printf("\n");
}
for(i=0;i<3;i++)
{
for(j=0;j<4;j++)
{
printf("%d",a[i][j]=0);
}
printf("\n");
}
for(i=0;i<3;i++)
{
for(j=0;j<16;j++)
{
printf("%d",a[i][j]=0);
}
printf("\n");
}
printf("            ");
for(i=0;i<3;i++)
{
for(j=15;j>11;j--)
{
printf("%d",a[i][j]=0);
}
printf("\n");
printf("            ");
}
printf("\r");
for(i=0;i<3;i++)
{
for(j=0;j<16;j++)
{
printf("%d",a[i][j]=0);
}
printf("\n");
}
}

 

i have done this using zeros so ur 's' will be with zeros

 

try this code
#include<stdio.h>
#include<conio.h>
void main()
{
int a[15][3],i,j;
clrscr();
for (i=0;i<3;i++)
{
for(j=0;j<16;j++)
{
printf("%d",a[j]=0);
}
printf("\n");
}
for(i=0;i<3;i++)
{
for(j=0;j<4;j++)
{
printf("%d",a[j]=0);
}
printf("\n");
}
for(i=0;i<3;i++)
{
for(j=0;j<16;j++)
{
printf("%d",a[j]=0);
}
printf("\n");
}
printf(" ");
for(i=0;i<3;i++)
{
for(j=15;j>11;j--)
{
printf("%d",a[j]=0);
}
printf("\n");
printf(" ");
}
printf("\r");
for(i=0;i<3;i++)
{
for(j=0;j<16;j++)
{
printf("%d",a[j]=0);
}
printf("\n");
}
}