1: main( ) 2: { 3: 4: static int a[ ] = {0,1,2,3,4}; 5: int *p[ ] = {a,a+1,a+2,a+3,a+4}; 6: int **ptr = p; 7: 8: ptr++; 9: printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); 10: 11: *ptr++; 12: printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); 13: 14: *++ptr; 15: printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); 16: 17: ++*ptr; 18: printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); 19: } plz explain how the *ptr++, *++ptr,++*ptr works?
Always remember the Precedence and the associativity of the operators: Refer the link http://en.wikipedia.org/wiki/Operators_in_C_and_C++ 1. Increment/Decrement(both Prefix and Postfix) has higher precedence than deference(*). 2. Deference and Prefix Increment/Decrement has same precedence but the associativity is from Right to left *ptr++: can be treated as *(ptr++) *++ptr: can be treated as *(++ptr) as associativity is Right to left ++*ptr: can be treated as ++(*ptr) as associativity is Right to left Sharanu, Amar
