Hello If I take a string declaration as below: char str[5]="Mike"; than the following statement does NOT produce error str[start] ^= str[end]; If I take a string declaration as below: char *str="Mike"; that the above mentioned statement str[start] ^= str[end]; DOES produce error. So I want to know , that if my string declaration is as in second case (char *str="Mike" than , how to write XOR statement so that it should not produce error. Thank You
buddy i tried out ur code char *str="MIKE"; str[0]^=str[4]; printf(" %s",str); it gives no error... so i dont get it were is ur problem?
micsom, you're probably using a different compiler, which one is it? Modifying a string constant should throw an error, since it's an operation you shouldn't perform. XOR-ing something with zero DOESN'T modify it, so mabye the compiler's outsmarting the lot of us. Try this: Code: char *str1="Mike"; char *str2=str1; xtr1[0]^=str[3]; printf("%s\n",str2);
I have tried it in my pc....I modified it a bit....and it is running without error.... my code is... Code: #include<stdio.h> #include<conio.h> void main() { char *str1="Mike"; char *str2=str1; str1[0]^=str1[4]; printf("%s\n",str2); getch(); } Is there anything wrong in my understanding??
Actually i first tried with th given code for which the output was: Code: (ike I don't know why.... But then when I changed str1[3] to str1[4], the problem got solved immediately....cna anyone explain me why??
Well as I said you shouldn't modify string constants so str1[<anything>]^=<anthing> should throw an error - a compile time error if nothing else. However if it works, to find out why 'M' xor 'e' produces '(' you'll need to look at an ASCII table and the binary values of those three characters. 'M' xor str1[4] = 'M', since str1[4]=0 (it's the terminating NULL). And as I said above, xor-ing anything with zero has no effect.
