Plz Help with this converter!

Hey everyone can someone plz help or guide me in the right direction.
i have to make a converter that will convert (Binary,Decimal,Octal,and Hex)
1-input base10-----output base2,base8, and base16.
2-input base2-------output base10,base8,and base16.
3-input base8-------output base2,base10, and base16.
4-input base16------output base2,base10,and base8.

i was able to write Decimal to Binary,Octal,and Hex with the Help of member Sabbir , like to his code that i used as guide.

my code that works but its completely wrong

Code:

int menu();
void Decimalnum();
void Hexadecimalnum();
void Octalnum();
void Binarynum();


int main()
{
	cout <<"Lab-4 Binary,Decimal,Octal,and Hex converter"<<endl;

	menu();
	return 0;
}
int menu()
{
	char choice;
	int flag = 1;
	while (flag ==1)
	{
	cout <<"Choose the base value option intput"<<endl;
	cout <<"1-Enter a decimal number,base10"<<endl;
	cout <<"2-Enter a hexadecimal number,base16"<<endl;
	cout <<"3-Enter a octal number,base2"<<endl;
	cout <<"4-Enter a binary number,base2"<<endl;
	cout <<" q Quit"<<endl <<endl;
	cout <<"Enter an option....";
	choice = _getch();
	cout <<endl <<endl;

switch(choice)
	{
	case '1':
		Decimalnum();
		break;
	case '2':
		Hexadecimalnum();
		break;
	case '3':
		Octalnum();
		break;
	case '4':
		Binarynum();
		break;
	case 'q': flag = 0;
		return 0;
	 }
  }
}
void Decimalnum()
{
	int num;
	cout <<"Option 1"<<endl;
	cout <<"This fucntion will convert a decimal number, base10 to hex base16, octal base8, and binary base2"<<endl<<endl;
	cout <<"Enter a decimal number,base10 :";
	cin >> num;
	cout <<"Base10 :";
	cout << num;
	system("pause");
	system("cls");
	return;
}
void Binarynum()
{
	int num,bin[100],i,j;
	cout <<"Base2:";
	cin >> num;
	for (i=0;num!=0;i++)
	{
		bin[i]= num%2;
		num=num/2;
	}
	for (j=i-1;j>=0;j--)
	{
		cout <<bin[j];
		return;
	}
}
void Octalnum()
{
	int num,r[10],i;
	cout <<"Option 3"<<endl;
	cout <<"This fucntion will convert a Octal number, base8 to hex base16, decimal base10, and binary base2"<<endl<<endl;
	cout <<"Enter a number to find it's octal :";
	cin >> num;
	cout <<"Base8 :",num;
	for (i=0;num!=0;i++)
	{
		r[i]=num%8;
		num = num/8;
	}
	i--;
	for(;i>=0;i--)
	cout <<r[i];
	cout <<endl;    
	system("pause");
	system("cls");
	return;
}
void Hexadecimalnum()
{
	int num,r[10],i;
	cout <<"Option 2"<<endl;
	cout <<"This fucntion will convert a hexadecimal number, base16 to decimal base10, octal base8, and binary base2"<<endl<<endl;
	cout <<"Base16:";
	cin >> num;
	for (i=0;num!=0;i++)
	{
		r[i]=num%16;
		num=num/16;
	}
	i--;
	for (;i>=0;i--)
	{
		if(r[i]==10)
            cout << "A";
        else if(r[i]==11)
            cout <<"B";
        else if(r[i]==12)
            cout <<"C";
        else if(r[i]==13)
            cout <<"D";
        else if(r[i]==14)
            cout <<"E";
        else if(r[i]==15)
            cout <<"F";
        else
            cout <<r[i];
    }
    cout <<endl;
	system("pause");
	system("cls");
	return;
}

 

srry small correction to be made

its member Shabbir
forgive me:disappoin

 

the code works fine but it only converts.
Decimal to binary
Decimal to Octal
Decimal to Hex
in that order and one at a time depending on user input

but what i want to do is
user input ---- base10(decimal #) example = 44
i want out output as :
base10=44
base2=00101100
base8=54
base16=2c

everthing as the same time

 

i am new to programming so sorry for being slow

so your saying that i do this:

void Decimal_to_rest()
{
_____________
then jst call
decimal_to_binary();
decimal_to_octal();
decimal_to_hex();
}

if so then i have tried that it doesn't let me do that :nonod:

 

i've tried everything :banghead: :banghead:

anyone else want to take a shot at it

Thank you

 

i'm not sure but i assume that you can always find a std method or at least a pre written code that works fine
i mean if this is not for leaning purpose
you can ise itoa

 

k so i am just about giving up :cuss: with this program, but i am going to attempt one last try.
i am getting a error in the following code.
error C2660: 'PrintBinary' : function does not take 1 arguments
error C2660: 'PrintOctal' : function does not take 1 arguments
error C2660: 'PrintHex' : function does not take 1 arguments

also i do need to make so changes to like adding my menu and other conversions but b4 i do that i just want to know if anyone point out if this it the correct way to go about??
Thanx for all the help:pleased:

Code:

#include "stdafx.h"
#include <iostream>
#include <math.h>
#include <string.h>
#include <algorithm>
#include "conio.h"
using namespace std;

void PrintOctal();
void PrintBinary();
void PrintHex();


int main ()
{
	int iMyNumber;
	cin >> iMyNumber;

		PrintBinary(iMyNumber);
		PrintOctal(iMyNumber);
		PrintHex(iMyNumber);
		cout << "Dec = " << iMyNumber <<endl;
		cin.get();
		return 0;
	
	return 0;
}

void PrintBinary(int iInteger)
{
	cout <<"Bin = ";
	for (int i = 31; i >= 0; --i)
	{
		std::cout << ((iInteger >> i) % 2);
	}

	cout << " " <<endl;
}

void PrintOctal(int iInteger)
{	
	using namespace std;
	cout << "Octal = ";
	for (int i = 10; i >=0; --i)
	{
		int iOctDigit =((iInteger >> (3*i)) % 8);
		cout << iOctDigit << "  ";
	}
	cout << endl;
}

void PrintHex(int iInteger)
{
	cout <<"Hex = ";
	for (int i = 7; i >= 0; --i)
	{
		int iHexDigit = ((iInteger >>(4*i)) % 16);
		if (iHexDigit < 10)
		{
			cout << "  " <<iHexDigit;
		}
		else
		{
			cout << "  " << (char) ('A' + (iHexDigit - 10));
		}
	}

 

Not only what Shabbir said, but also your requirements seem to have changed:

We are not going to write your code for you, but we can help you get unstuck. But this requires you to put some effort in.

First you have to decide *exactly* what you want the program to do, because without that nobody stands a chance of getting anything right.

Second you have to have a go at it yourself. You say you've tried everything, but there is no evidence of that. What is your latest attempt at the program, and where are you stuck? What is it doing that you didn't expect, or what isn't it doing that you did expect? What input did you give, what output did you get, and why is that output wrong? Have you identified the line of code where things start going wrong?

Have you tried adding some debugging statements (printf is ideal for this) to display the values of relevant variables at key points in your code? I find this very useful for helping me debug a program that I can't get working. Better still if you can step through it in a debugger, then you can see exactly what it's doing and how that compares with what you THINK the code does.

 

Thank you for your reply and I don't know how else I can explain myself I never asked for anyone to write my program for me!!!. in my original post. I posted my attempt with the a problem. Then I was told to call the functions, so I tried that and posted what I tried and that didn't work so, Then I tried to do the program a different way using strings (which I don't know much) and I also stated that I need to make some changes I didn't add the menu and rest of the conversions because first I wanted to know if this would work.*Last but not least I clearly posted that I am completely new to programing I started last month*Well thanks again for your help*

 

People often post homework assignments here expecting us just to do it for them.

Take my questions one at a time. I have been programming since 1981 so I have a bit of a clue. You should be able to answer them all as they are not difficult, but I appreciate it can seem a bit much. If you answer my questions in as much detail as possible (just make your best effort) then we should be able to get this working properly together.

 

k so i going to post my code first which is a real mess and missing some code, then i will explain myself.

Code:

#include <cstdlib>
#include <iostream>
#include <iomanip>
#include <conio.h>
#include <math.h>
#include <bitset>
#include <string>
#include <stdlib.h>
#include <stdio.h>
using namespace std;
#define max 1000


int menu();
void Decimalnum();
void Binarynum();
void Octalnum();
void Hexadecimalnum();

void D2B();
void D2O();
void D2H();

void B2D();
void B2O();
void B2H();

void O2D();
void O2B();
void O2H();

void H2D();
void H2O();
void H2B();

int main()
{
    cout <<"Lab-4 Binary,Decimal,Octal,and Hex converter"<<endl;

    menu();
    return 0;
}
int menu()
{
    char choice;
    int flag = 1;
    while (flag ==1)
    {
    cout <<"Choose the base value option intput"<<endl;
    cout <<"1-Enter a decimal number,base10"<<endl;
    cout <<"2-Enter a binary number,base2"<<endl;
    cout <<"3-Enter a octal number,base2"<<endl;
    cout <<"4-Enter a hexadecimal number,base16"<<endl;
    cout <<" q Quit"<<endl <<endl;
    cout <<"Enter an option....";
    choice = _getch();
    cout <<endl <<endl;

switch(choice)
    {
    case '1':
        Decimalnum();
        break;
    case '2':
        Binarynum();
        break;
    case '3':
        Octalnum();
        break;
    case '4':
        Hexadecimalnum();
        break;
    case 'q': flag = 0;
        return 0;
     }
  }
}
void Decimalnum()
{
    int num;
    cout <<"Option 1"<<endl;
cout <<"This fucntion will convert a decimal number, base10 to hex base16, octal base8, and binary base2"<<endl<<endl;
    cout <<"Enter a decimal number,base10 :";
    cin >> num;
    cout <<"Base10 :";
    cout << num;
    int D2B();
    int D2O();
    int D2H();
    system("pause");
    system("cls");
    return;
}





void Binarynum()
{
    int num;
    cout <<"Option 2"<<endl;
cout <<"This fucntion will convert a Binary number, base2 to hex base16, octal base8, and binary base10"<<endl<<endl;
    cout <<"Enter a Binary number,base10 :";
    cin >> num;
    cout <<"Base2  :";
    cout << num;
    int B2D();
    int B2O();
    int B2H();
    system("pause");
    system("cls");
    return;
}
void Octalnum()
{
    int num;
    cout <<"Option 3"<<endl;
cout <<"This fucntion will convert a Octal number, base8 to hex base16, decimal base10, and binary base2"<<endl<<endl;
    cout <<"Enter a Octal number,base8 :";
    cin >> num;
    cout <<"Base8 :";
    cout << num;
    int O2D();
    int O2B();
    int O2H();
    system("pause");
    system("cls");
    return;
}
void Hexadecimalnum()
{
    int num;
    cout <<"Option 4"<<endl;
cout <<"This fucntion will convert a Hexadecimalnum number, base16 to decimal base10, octal base8, and binary base2"<<endl<<endl;
    cout <<"Enter a Hex number,base16 :";
    cin >> num;
    cout <<"Base16 :";
    cout << num;
    int H2D();
    int H2O();
    int H2D();
    system("pause");
    system("cls");
    return;
}
void D2B(){
   int n,bin[100],i,j;
    cout<<"Enter Base10 : ";
    cin >>n;
    cout<<"Base2 = ",n;
    for(i=0;n!=0;i++)
    {
        bin[i]=n%2;
        n=n/2;
    }
    for(j=i-1;j>=0;j--)
    {
        cout<<bin[j];
    }
    cout<<endl;
    system("pause");
    return;
}
void D2O(){
int num,r[10],i;
    cout <<"Enter Base10 :";
    cin >> num;
    cout <<"Base8 = ",num;
    for (i=0;num!=0;i++)
    {
        r[i]=num%8;
        num = num/8;
    }
    i--;
    for(;i>=0;i--)
    cout <<r[i];
    cout <<endl;    
    system("pause");
    system("cls");
    return;
}
void D2H(){
    int num,r[10],i;
    cout <<"Enter Base10:";
    cin >> num;
    cout <<"Base16 = ";
    for (i=0;num!=0;i++)
    {
        r[i]=num%16;
        num=num/16;
    }
    i--;
    for (;i>=0;i--)
    {
        if(r[i]==10)
            cout << "A";
        else if(r[i]==11)
            cout <<"B";
        else if(r[i]==12)
            cout <<"C";
        else if(r[i]==13)
            cout <<"D";
        else if(r[i]==14)
            cout <<"E";
        else if(r[i]==15)
            cout <<"F";
        else
            cout <<r[i];
    }
    cout <<endl;
    system("pause");
    system("cls");
    return;
}
void B2D(){
    std::string binary2decimal_cstr;
    std::cout<<"Enter Base2 : ";
    std::cin>>binary2decimal_cstr;
    std::cout<<"Base10 = " <<std::bitset<32>(binary2decimal_cstr).to_ulong();
    std::cout<<std::endl;
    system("pause");
    return;
}
void B2O(){
        char num_str[50];
    cout<<"Enter Base2 : ";
    cin>>num_str;
    long num_1 = strtol(num_str,NULL,2);
    ltoa(num_1,num_str,8);
    cout<<"Base8 = " <<num_str<<endl<<endl;
    system("pause");
    return;
}
void B2H(){
    
 long int binary,hex=0,j=1,rem;
   printf("Enter Base2 : ");
   scanf("%ld",&binary);
   while(binary!=0){
   rem=binary%10;
   hex=hex+rem*j;
   j=j*2;
   binary=binary/10;
}
 printf("Base16 : %lX \n",hex);
 system("pause");
 return;
}
void O2D(){
    int i,octnum,decnum=0,arr[20];
    cout <<"Enter Base8 : ";
    cin>>octnum;
    for(i=0;octnum>0;i++)
    {
      arr[i]=octnum%10;
      octnum=octnum/10;
      }
      cout<<i;
      for(int power=0,j=0;j<i;j++,power++)
      {
              decnum = decnum + arr[j] * pow(8.0,power);
              }
      cout <<"Base10 = "<<decnum;
      system("pause");
      return;
}
void O2B(){
    char oct[max];
    long int i=0;
    cout<<"Enter Base2: ";
    cin >>oct;
    cout <<"Base2 = ";
    while(oct[i]){
    switch(oct[i])
    {
     case '0': cout<<"000"; break;
     case '1': cout<<"001"; break;
     case '2': cout<<"010"; break;
     case '3': cout<<"011"; break;
     case '4': cout<<"100"; break;
     case '5': cout<<"101"; break;
     case '6': cout<<"110"; break;
     case '7': cout<<"111"; break;
     default:break;
                   }
    i++;
    }

    system("pause");
    return;
}
void O2H(){

//I know in order to get hex octal number has to first convert into binary and then into hex but I cannot figure this out. 

}
    
void H2D(){
    int num;
    printf("Enter Base16 : ");
    scanf("%lX",&num);
    printf("Base2 = %ld \n",num);
    system("pause");
    return;
}
void H2O(){
    int num;
    printf("Enter Base16 : ");
    scanf("%lX",&num);
    printf("Base8 = %o \n",num);
    system("pause");
    return;
}
void H2B(){
    
//I can't figure this one out as well I know it should be the opposite of binary to Hex it won't work .

}

 

So as you see I have a lot of ---#include’s--- because I am not sure what should be included.
First ---- I made 4 functions Decmalnum,Binarynum…….. and then tried to call the my conversion function in them like D2B(),D2O()…so on (which doesn’t work ) .
Second ---- as you see I have some of the code in C instead of C++ it because most of my code is of the internet as I can’t figure it out myself. So if someone helps me convert it to C++ pls.
Last ---- I am missing some code for which I understand the logic but can seem to put it together.
I know I am going to hear a lot for this code but I can’t get help for anyone regarding this. :worried::worried:
Thank you for any or all your help :nice::nice:

 

C is a subset of C++ so all C code is also valid C++ code.

You don't really need all 12 conversion functions. Just pick one as your "internal" format - decimal is probably easiest, then take the input in whatever format, convert it to the internal format, then display the three or four (depending on your requirements) formats. Then you will only need O2D, H2D, B2D, and D2O, D2H and D2B.

In Decimalnum() you seem confused about how to call functions. If you prefix a function name with a type then that is a function definition, not a function call. Strangely in menu() you have the correct syntax for calling functions Decimalnum() etc.

Focussing on Decimalnum(), you get the user to input the number they want to convert it and display it. You then call D2B, D2O and D2H, each of which asks the user to input their original number again. It'd be better to store that number in a variable, then pass that variable into those three functions.

A comment on the amount of code you have written. Don't try to write the whole program in one go. It's not an essay, and the compiler does not only have to be called once. Start with a few lines of code (just your menu for example), compile it, if that works run it, and make sure that works OK. Then add a few more lines of code and make sure they work OK as well. Bit by bit build up your program. Otherwise you're going to repeat the same errors over and over again (like your wrong syntax for calling functions like D2B) and you'll get thousands of errors from the compiler and you won't have a clue where to start. If you only have a few lines of code that could go wrong then this limits the scope as to what the compiler will complain about.

You don't need to set flag to zero in main, because of the return statement. If you have a return statement then the function returns at that point, not some time later. Do either "case 'q': flag=0; break;" or "case 'q': return 0;".

 

thank you, so is this what your talking about ??

Code:

int main()
{
    cout <<"Lab-4 Binary,Decimal,Octal,and Hex converter"<<endl;

    menu();
    return 0;
}
int menu()
{
    char choice;
    int flag = 1;
    while (flag ==1)
    {
    cout <<"Choose the base value option intput"<<endl;
    cout <<"1-Enter a decimal number,base10"<<endl;
    cout <<"2-Enter a binary number,base2"<<endl;
    cout <<"3-Enter a octal number,base8"<<endl;
    cout <<"4-Enter a hexadecimal number,base16"<<endl;
    cout <<" q Quit"<<endl <<endl;
    cout <<"Enter an option....";
    choice = _getch();
    cout <<endl <<endl;

switch(choice)
    {
    case '1':
        Decimalnum();
        break;
    case '2':
        Binarynum();
        break;
    case '3':
        Octalnum();
        break;
    case '4':
        Hexadecimalnum();
        break;
    case 'q':
        return 0;
     }
  }
}
void Decimalnum()
{
    int num;
    cout <<"Option 1"<<endl;
cout <<"This fucntion will convert a decimal number, base10 to hex base16, octal base8, and binary base2"<<endl<<endl;
    cout <<"Enter a decimal number,base10 :";
    cin >> num;
    cout <<"Base10 :";
    cout << num <<endl;
    D2B(num);
    D2O(num);
    D2H(num);
    system("pause");
    system("cls");
    return;
}
void D2B(int n){
   int bin[100],i,j;
    
    cout<<"Base2 = ",n;
    for(i=0;n!=0;i++)
    {
        bin[i]=n%2;
        n=n/2;
    }
    for(j=i-1;j>=0;j--)
    {
        cout<<bin[j];
    }
    cout<<endl;
    return;
}
void  D2O(int num){
int r[10],i;
    
    cout <<"Base8 = ",num;
    for (i=0;num!=0;i++)
    {
        r[i]=num%8;
        num = num/8;
    }
    i--;
    for(;i>=0;i--)
    cout <<r[i];
    cout <<endl;    
    return;
}
void D2H(int num){
    int r[10],i;
    
    cout <<"Base16 = ";
    for (i=0;num!=0;i++)
    {
        r[i]=num%16;
        num=num/16;
    }
    i--;
    for (;i>=0;i--)
    {
        if(r[i]==10)
            cout << "A";
        else if(r[i]==11)
            cout <<"B";
        else if(r[i]==12)
            cout <<"C";
        else if(r[i]==13)
            cout <<"D";
        else if(r[i]==14)
            cout <<"E";
        else if(r[i]==15)
            cout <<"F";
        else
            cout <<r[i];
    }
    cout <<endl;
    return;
}

so now how do it reset of the conversions ?? because i think i still need one of each like B2D() , O2D() and H2D(), than i can re use the decimal function again but i get figure out how to do B2D() , O2D() and H2D() using integers i am using strings and i cant all my Decimal functions because of it. Help plz :wacky:

 

Did you compile this code? Did you get any errors?
If not, did it run OK and do what you expected?
Did you think up any possible boundary conditions and test that the code worked there?

Obviously the code as is will fail at compile time as Binarynum() and the other two are missing, but for now you could use stub code like:

Code:

void Binarynum()
{
cout << "Not written yet" << endl;
}

VERY BIG HINT FROM SOMEONE WHO HAS PROBABLY BEEN DOING THIS FOR LONGER THAN YOU HAVE BEEN ALIVE: do *not* proceed with anything else in this reply until you've done the above. I've already explained why.




So, now you've got the above code working:

B2D, O2D and H2D will basically be the reverse of the functions you've already coded. For example in binary, start with total=0, then if the rightmost bit is 1 then add 1; if the next bit is 1 then add 2; if the next bit is 1 then add 4, and for each subsequent bit add the next power of 2. (Don't use pow(); just double the column value on each iteration.)

Oct and hex are a bit more complicated but not much: first add the rightmost digit of the octal number, then add the next digit multiplied by 8, then the next digit multiplied by 64 and so on. And for hex you will need to check if the digit is 0-9 or A-F and add 0-9 or 10-15 multiplied by the current column value (1, 16, 256 etc).

If you use strings for these three functions then you can calculate the value of the digit very easily by just subtracting '0'. You don't need to know the ASCII codes. So '7'-'0'=7. For hex, for instance, 'c'-'a'=2, but c is 12 so add 10 to that: 'c'-'a'+10=12. You can use an int for the column value, and as you scan the string from right to left start with 1 then multiply it by 2, 8 or 16 depending on whether you're doing binary, oct or hex.

 

ok so far this code run and does exactly what i want, i am still working on the rest:crazy:

Code:

#include "stdafx.h"
#include <cstdlib>
#include <iostream>
#include <iomanip>
#include <conio.h>
#include <math.h>
#include <bitset>
#include <string>
#include <stdlib.h>
#include <stdio.h>
using namespace std;
#define max 1000


int menu();
void Decimalnum();
void Binarynum();
void Octalnum();
void Hexadecimalnum();

void D2B(int);
void D2O(int);
void D2H(int);


int main()
{
    cout <<"Lab-4 Binary,Decimal,Octal,and Hex converter"<<endl;

    menu();
    return 0;
}
int menu()
{
    char choice;
    int flag = 1;
    while (flag ==1)
    {
    cout <<"Choose the base value option intput"<<endl;
    cout <<"1-Enter a decimal number,base10"<<endl;
    cout <<"2-Enter a binary number,base2"<<endl;
    cout <<"3-Enter a octal number,base2"<<endl;
    cout <<"4-Enter a hexadecimal number,base16"<<endl;
    cout <<" q Quit"<<endl <<endl;
    cout <<"Enter an option....";
    choice = _getch();
    cout <<endl <<endl;

switch(choice)
    {
    case '1':
        Decimalnum();
        break;
    case '2':
        Binarynum();
        break;
    case '3':
        Octalnum();
        break;
    case '4':
        Hexadecimalnum();
        break;
    case 'q': flag = 0;
        return 0;
     }
  }
}
void Decimalnum()
{
    int num;
    cout <<"Option 1"<<endl;
cout <<"This fucntion will convert a decimal number, base10 to hex base16, octal base8, and binary base2"<<endl<<endl;
    cout <<"Enter a decimal number,base10 :";
    cin >> num;
    cout <<"Base10 :";
    cout << num <<endl;
    D2B(num);
    D2O(num);
    D2H(num);
    system("pause");
    system("cls");
    return;
}
void Binarynum()
{
	cout <<"Not written yet"<<endl;
    system("pause");
    system("cls");
    return;
}
void Octalnum()
{
   cout <<"Not written yet"<<endl;
    system("pause");
    system("cls");
    return;
}
void Hexadecimalnum()
{
    cout <<"Not written yet"<<endl;
    system("pause");
    system("cls");
    return;
}
void D2B(int num){
   int bin[100],i,j;
  
    cout<<"Base2 = ",num;
    for(i=0;num!=0;i++)
    {
        bin[i]=num%2;
        num=num/2;
    }
    for(j=i-1;j>=0;j--)
    {
        cout<<bin[j];
    }
    cout<<endl;
    return;
}
void D2O(int num){
	int r[10],i;
   
    cout <<"Base8 = ",num;
    for (i=0;num!=0;i++)
    {
        r[i]=num%8;
        num = num/8;
    }
    i--;
    for(;i>=0;i--)
    cout <<r[i];
    cout <<endl;    
    return;
}
void D2H(int num){
    int r[10],i;
    
    cout <<"Base16 = ",num;
    for (i=0;num!=0;i++)
    {
        r[i]=num%16;
        num=num/16;
    }
    i--;
    for (;i>=0;i--)
    {
        if(r[i]==10)
            cout << "A";
        else if(r[i]==11)
            cout <<"B";
        else if(r[i]==12)
            cout <<"C";
        else if(r[i]==13)
            cout <<"D";
        else if(r[i]==14)
            cout <<"E";
        else if(r[i]==15)
            cout <<"F";
        else
            cout <<r[i];
    }
    cout <<endl;
    return;
}