Passing a two dimensional array to a function

I tried two methods for this and it worked.

First Method :

Code:

#include<stdio.h>

void fun(int *a,int col , int row)
{
int i,j;
for(i=0;i<3;i++)
{
for(j=0;j<4;j++)
{
printf(" %d\n",*(a+j));
}
a=a+4;
}
}


main()
{

int arr[4][3] = {{1,2,3},{4,5,6},{7,8,9},{10,11,12}};

fun(&arr[0][0],3,4);

}

Second Method :

Code:

#include<stdio.h>

void fun(int a[3][3],int col , int row)
{
int i,j;
for(i=0;i<3;i++)
{
for(j=0;j<3;j++)
{
printf(" %d\t",a[i][j]);
}
printf("\n\n");
}
}


main()
{

int arr[3][3] = {{1,2,3},
                 {4,5,6},
                 {7,8,9}};
printf("%u\n",arr);
fun(arr,3,3);

}

 

Hi,

just a small correction...ur function should rather used passed row an col values insetad of hardcoding them...somehting like this....

Code:

void fun(int *a,int col , int row)
{
int i,j;
for(i=0;i<col ;i++)
{
for(j=0;j<row;j++)
{
printf(" %d\n",*(a+j));
}
a=a+row;
}
}

 

Learning how to indent code as well would be a priority as well.

In response to "method 1".
http://c-faq.com/aryptr/ary2dfunc2.html

> I tried two methods for this and it worked.
Be careful of thinking that "works for me" is any substitute for knowing what is guaranteed by the standard. There are hundreds (possibly thousands) of compilers out there, and you've just tested one of them with a single experiment.