Nested Loop Simulation

Code:

#include <stdio.h>
#include <conio.h>

int A(int x)
{
	x++;
	return(x+1);
}

int B(int y,int z)
{
	int t, i;
	
	t=1;
	for(i=1;i<=y;i++)
	t*=i;
	
	for(i=1;i<=z; i++)
	t+=i;
	return(t);
}

main()
{
	int m,n,x;
	
	m=2;
	n=4;
	
	printf("%d\n", B(m,n)+B(n,m));
	printf("%d\n",A(B(m,n)));
	
	m=3;
	n=A(n);
	m=B(n,m);
	printf("%d\n%d\n%d", n,m,B(n,m));
	
	getch();
	return 0;
	
}

by simulation, i am able to get the values for the first two printf.

and on the 3rd printf,how come m=726 and B(n,m)=264261?
i run the code because i do not have the idea how to simulate to get the values for m and B(n,m)

please! somebody explain it.this will help me pass my exam. Nested Loop Simulation

 

The first printfs call by value so they don't change n or m when they return. After that,
you've assigned both n and m values

Code:

m=3;
n=A(n);
m=B(n,m);

n = A(4) = 6
m = B(6, 3) = 726

Code:

printf("%d\n%d\n%d", n,m,B(n,m));

here your parameter list to printf looks like
6, 726, B(6, 726)

from the B definition

Code:

B(6, 726)

t=1
for(i=1;i<=6;++i)
     1 x 1 =   1
     1 x 2 =   2
     2 x 3 =   6
     6 x 4 =  24
    24 x 5 = 120
   120 x 6 = 720

t now equals 720

for(i=1; i<=726; ++i)
   720 + 1 = 721
   721 + 2 = 723
   723 + 3 = 726
      ...

I don't know the value of t with each iteration, but it's obvious that t will grow a bit

 

Thank You Hobbyist