Hi All, This may not b a new question to most of you but since am a newbie, please consider answering this. For languages like c/c++ and java, how does mod % operator work with negative numbers. for e.g and trying to fetch the output of -3%2 . The actual output is -1 whereas it should be just one. Could you help me to come out with a solution on how shall I generate the correct output for negative numbers. thanks

Looks like it's not as simple as that: http://en.wikipedia.org/wiki/Modulo_operation Visual C++ 2008 test code: Code: void test39() { for (int i=5; i>=-5; i--) { for (int j=-5; j<=5; j++) { if (j) printf("%4d",i%j); fflush(stdout); } printf("\n"); fflush(stdout); } } Output: Code: 0 1 2 1 0 0 1 2 1 0 4 0 1 0 0 0 0 1 0 4 3 3 0 1 0 0 1 0 3 3 2 2 2 0 0 0 0 2 2 2 1 1 1 1 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 -1 -1 -1 -1 0 0 -1 -1 -1 -1 -2 -2 -2 0 0 0 0 -2 -2 -2 -3 -3 0 -1 0 0 -1 0 -3 -3 -4 0 -1 0 0 0 0 -1 0 -4 0 -1 -2 -1 0 0 -1 -2 -1 0 This seems correct to me. -3 % 2 calculates the remainder after the division -3 / 2. There are -1 2's in -3 so -3 / 2 = -1. After subtracting -1*2 from -3 you're left with -1. If you think it should be 1, does that mean you think the division should return -2? If you subtract X from -3 to get +1 then X has to be -4, i.e. -2*2.