#include <stdio.h> main() { char a[5] = "abcd"; int b = 3; printf("%c\n",a); printf("%c\n",((char *) b)[(int) a]); } i get d d as output.. a[3] = d..i get it.. what ((char *)b)[(int) a] doing there... all i can understand from the above is that it is doing something that is producing lyk i[a] from a type.. wats happening der actually n how is it happening???
It's casting b, which is an integer, to a char*, then casting a, which is an array but taken as a char* in this context, to an integer, then using pointer[offset] syntax to address the 'd'. pointer[offset] is just worked out as pointer+offset*sizeof(*pointer) so there's no difference between a and b[a], providing b and a in the latter case are cast correctly.
