I have seen this one in this forum only..but i couldnt understand how come the answer is 10 for the below ??? int z,x=5,y=-10,a=4,b=2; z = x++ - --y * b / a; then output of z..???

i think the value of z is 10. how:- step 1:- --y is evaluated which become -11. step 2:- (-11) will multiple with b which become -22 step 3:- this (-22) get devided by a now intermidiate result will be -5 step 4:- now expression become as z=x++ - -5; step 5 :- -5 become +5 step 6:- here the main game start the priority of post-increment is lower then assignement operater that's why first the value of x which is 5 is added with intermidiat result +5 which become 10 and this 10 get assigne into variable z . step 7:- variable x increment its value by 1 and become 6.

Don't forget that x++ means POSTincrement and ++x means PREincrement. That means before and after, and is usually before or after some execution point. So the equation in some senses (but definitely not all) is equivalent to: Code: --y; z = x - y * b / a; x++; This should be a lot easier to evaluate. First y is decremented to -11. Then z=5 - -11 * 2 / 4 =5 - -22/4 =5 - -5 =5 + 5 =10. Then x is incremented.