Help with simple program

I'm very new to programming and ive been trying to figure out this problem for a few days and still have no luck, I cant figure out how to get the average to ignore an out of range number. Also the range is the max- the min which i cant get to work either please help.

Code:

#include <iostream>
using namespace std;

int main()
{
double x;
double sum = 0.0;
int number = 0;
double average;
double max = 0;
double min = 0;

while (cin>>x)

{
if ((x < 0) || (x > 100))
{
cin.ignore(3,'\n');

cout << "Out of range ; ignored." << endl;
}

if (x > max)
max = x;

if (min > x)
x = min;

sum += x;
number++;
}
if (number > 0)
{
average = sum / number;
cout<<"The average is "<< average;
cout<<" The range is "<< max - min;
cout << endl;
}
return 0;
}

 

What's the objective of the program??

 

You're starting min at 0, so nothing will be less than it. You need to start it at the maximum (100).

You need to add "continue;" after the out of range check to skip the rest of the while loop:

Code:

if ((x < 0) || (x > 100))
{
    cin.ignore(99,'\n');
    cout << "Out of range ; ignored." << endl;
    continue;
}

The line x = min needs to be min = x.