Need help with option parsing arguments!!

Discussion in 'C' started by euler, Mar 13, 2011.

  1. euler

    euler New Member

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    Hey!!

    I have a project for my university to be done.I have almost complete the whole program but i have little problem(i think...)

    the exercise tells me that the call of the program must be something like this:
    progname -c C1 C2 -f file1 file2 -o fileoutput

    C1,C2 are integers numbers
    can anyone plz help me..

    thanks.!
     
  2. eriyer

    eriyer New Member

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    Code:
    /* something on the foll lines */
    
    void main(int argc, char* argv[])
    {
    	int i, c1,  c2, opt = 0, error = 0;
    	char *file1, *file2, *fileoutput;
    	
    	for( i = 1; i < argc && opt <= 'o' ; i++ )
    	{
    		if( ! strcmp(argv[ i ], "-c" )
    		{
    			if( opt == 0 )
    			{
    				opt = 'c';
    				continue;
    			}
    			else
    			{
    				error = 1;
    			}
    				
    		}
    		else if( opt == 0 )  /* expecting -c */
    			error = 1;
    		
    		if( ! strcmp(argv[ i ], "-f" )
    		{
    			if( opt == 'e' )
    			{
    				opt = 'f';
    				continue;
    			}
    			else
    			{
    				error = 1;
    			}
    		}
    		else if( opt == 'e' )  /* expecting -f */
    			error = 1;
    		
    		if( ! strcmp(argv[ i ], "-o" )
    		{
    			if( opt == 'h' )
    			{
    				opt = 'o';
    				continue;
    			}
    			else
    			{
    				error = 1;
    			}
    		}
    		else if( opt == 'h' ) /* expecting -o */
    			error = 1;
    		
    		if( error )
    		{
    			printf("parameters to program incorrect\n");
    			exit(1);
    		}
    		
    		if( opt == 'c' )
    		{
    			c1 = atoi(argv[ i ]);
    			opt = 'd';   /* next param for 2nd integer */
    		}
    			
    		if( opt == 'd' )  /* 2nd integer */
    		{
    			c2 = atoi(argv[ i ]);
    			opt = 'e';   /* prep to read file names */
    		}
    		
    		if( opt == 'f' )
    		{
    			f1 = argv[ i ];
    			opt = 'g'; 
    		}
    		
    		if( opt == 'g' )  /* 2nd filename */
    		{
    			f2 = argv[ i ];
    			opt = 'h'; 
    		}
    		
    		if( opt == 'o' )
    		{
    			fileoutput = argv[ i ];
    			opt = 'q';
    		}
    	}
    	
    	if( opt != 'q' || i < argc )
    	{
    		printf("parameters to program incorrect\n");
    		exit(1);
    	}
    		
    	/* rest of your program below */
    }
     
  3. mthushara

    mthushara New Member

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    Code:
    void main(int argc, char* argv[])
    {
    	int c1 = 0,  c2 = 0;
    	char *file1 = NULL, *file2 = NULL, *fileoutput = NULL;
    	bool bNoError = false;
    
    	if(argc != 9)
    	{
    		printf("invalid number of arguments\n");
    		printf("usage : progname -c C1 C2 -f file1 file2 -o fileoutput\n");
    		exit(1);
    	}
    
    	//////////////////////////////////////////////////////////////////////////
    
    	int i = 1;
    
    	if (strcmp(argv[i],"-c") == 0)
    	{	
    		i++;
    		c1 = atoi(argv[i]);
    
    		i++;
    		c2 = atoi(argv[i]);
    
    		bNoError = true;
    	}
    
    	i++;
    	if (strcmp(argv[i],"-f") == 0)
    	{	
    		i++;
    		file1 = argv[i];
    
    		i++;
    		file2 = argv[i];
    
    		bNoError &= true;
    	}
    
    	i++;
    	if (strcmp(argv[i],"-o") == 0)
    	{	
    		i++;
    		fileoutput = argv[i];
    
    		bNoError &= true;
    	}
    
    	//////////////////////////////////////////////////////////////////////////
    	
    
    	if(bNoError == false)
    	{
    		printf("parameters to program incorrect\n");
    		exit(1);
    	}
    	else
    	{
    		printf("argv[1] : %s\n",argv[1]);
    		printf("argv[2] : %d\n",c1);
    		printf("argv[3] : %d\n",c2);
    		printf("argv[4] : %s\n",argv[4]);
    		printf("argv[5] : %s\n",file1);
    		printf("argv[6] : %s\n",file2);
    		printf("argv[7] : %s\n",argv[7]);
    		printf("argv[8] : %s\n",fileoutput);
    	}
    }
     

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