Hello world, my name is adrian and im a newbie... ]m trying to write a program which tests whether a natural number can be written as the sum of the squares of two not null integers. I am using an auxiliary function to test whether a natural number is a square or not. Seems that compiling errors are produced even by this initial function Cant figure out whats wrong though.... Please somebody help im a big ****.... thanks in advance adrian what i did is this: Code: #include <stdio.h> #include <math.h> int sqtest (double n); { int a; if(double sqrt(n)==double floor (sqrt(n))) a=1; else a=0; return a; } int main () {double n, i, a; a=0; i=1; printf("input n\n"); scanf("%d",&n); while ((i<=double sqrt(n))&&(sqtest(n-i*i)!=0)) {i=i+1; } if(i<double sqrt(n)) printf("n decomposable as sum of squares of:\n" i, double sqrt(n-i*i)); else printf("n indecomposable nontrivially\n"); return(); } ==================================== figured out that there might be not necessity of putting the "double", so i took them out and the code changed into sth like this: Code: int sqtest (double n); { int a; if(sqrt(n)==floor (sqrt(n))) a=1; else a=0; return a; } .......................... but still it does not work can sb help me please im really in a big -------- Thanks in advance guys! ^^

I'm not sure why you would want a square root function for the program you've described. To determine if x can be written as a*a+b*b surely you just need a pair of loops, one nested inside the other, to test values of a and b to a suitable maximum, then "if (x==(a*a+b*b)) { /* it can */ }".