grade prediction program

here is my code i get an error of call of non function in lines 29, 34, 39 and 44


apprecite help or an alternate code if possible

here is code

Code:

 int main (void)
{
  char desiredgrade;
  double min_average;
  double currentaverage;
  double weight;
  double score;
  printf("Please enter your desired grade: \n");
  scanf("%c", &desiredgrade);
  printf("Please enter your minimum average required:  \n");
  scanf("%lf", &min_average);
  printf("Please enter your current average in course:  \n");
  scanf("%lf", &currentaverage);
  printf("Please enter how much the final counts as a percentage of the course grade:  \n");
  scanf("%lf", &weight);
  if ( 92<=desiredgrade && desiredgrade>=100)
{
  score=(min_average-(100-weight)(currentaverage/100)+(100/weight));
  printf("You need a score of %.2f on the final to get A\n",score);
}
  else if (84<=desiredgrade && desiredgrade>=91)
{
  score=(min_average-(100-weight)(currentaverage/100)+(100/weight));
  printf("You need a score of %.2f on the final to get B\n",score);
}
  else if (76<=desiredgrade && desiredgrade>=83)
{
  score=(min_average-(100-weight)(currentaverage/100)+(100/weight));
  printf("You need a score of %.2f on the final to get C\n",score);
}
  else if (68<=desiredgrade && desiredgrade>=75)
{
  score=(min_average-(100-weight)(currentaverage/100)+(100/weight));
  printf("You need a score of %.2f on the final to get D\n",score);
  return 0 ;
}
  return score ;
}

 

C does not understand that this -> (x)(y) means x times y.
It thinks that you are trying to call function "x" with argument "y"
All you need to do is change every occurance of (x)(y) with (x)*(y)