Dynamic memory allocation with try catch block

I am trying to write a function to do dynamic memory allocation with a try catch block, so that I don't have to manually write a try catch block each time I want to allocate memory for an array. The code bellow is supposed to do that, but it outputs:

Allocated memory for small array
Segmentation fault

So apparently the function creates a copy of the array and allocates memory for the copy, but not for the original array. How do I fix this? Thanks in advance.

Code:

# include <iostream>
# include <fstream>
# include <string>
# include <cstring>
# include <sstream>
# include <time.h>
# include <iomanip>
# include <vector>

using namespace std;

template <class T>
bool SafeArrayAlloc(T *array, int Size)
{
	try 
	{
		array=new T[Size];
	}
	catch(bad_alloc&) 
	{
		return false;
	}
	return true;
}

int main(int argc, char * argv[])
{
	int big, small;
	int *big_array, *small_array;

	big=3000000000;
	small=10;

	if (!SafeArrayAlloc(&small_array, small))
	{
		cout <<"Unable to allocate memory for small array"<<endl;
	}
	else 
	{
		cout <<"Allocated memory for small array"<<endl;
		for (int i=0;i<small;i++) small_array[i]=0;
		for (int i=0;i<small;i++) small_array[i]=i;
		for (int i=0;i<small;i++) cout <<small_array[i]<<endl;
	}
	
	if (!SafeArrayAlloc(&big_array, big))
	{
		cout <<"Unable to allocate memory for big array"<<endl;
	}
	else 
	{
		cout <<"Allocated memory for big array"<<endl;
		for (int i=0;i<big;i++) big_array[i]=0;
		for (int i=0;i<big;i++) big_array[i]=i;
		for (int i=0;i<big;i++) cout <<big_array[i]<<endl;
	}
	
	return EXIT_SUCCESS;
}