Dynamic memory allocation with try catch block

Discussion in 'C++' started by BrainInVat, Jul 1, 2010.

  1. BrainInVat

    BrainInVat New Member

    Jul 1, 2010
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    I am trying to write a function to do dynamic memory allocation with a try catch block, so that I don't have to manually write a try catch block each time I want to allocate memory for an array. The code bellow is supposed to do that, but it outputs:

    Allocated memory for small array
    Segmentation fault

    So apparently the function creates a copy of the array and allocates memory for the copy, but not for the original array. How do I fix this? Thanks in advance.
    # include <iostream>
    # include <fstream>
    # include <string>
    # include <cstring>
    # include <sstream>
    # include <time.h>
    # include <iomanip>
    # include <vector>
    using namespace std;
    template <class T>
    bool SafeArrayAlloc(T *array, int Size)
    		array=new T[Size];
    		return false;
    	return true;
    int main(int argc, char * argv[])
    	int big, small;
    	int *big_array, *small_array;
    	if (!SafeArrayAlloc(&small_array, small))
    		cout <<"Unable to allocate memory for small array"<<endl;
    		cout <<"Allocated memory for small array"<<endl;
    		for (int i=0;i<small;i++) small_array[i]=0;
    		for (int i=0;i<small;i++) small_array[i]=i;
    		for (int i=0;i<small;i++) cout <<small_array[i]<<endl;
    	if (!SafeArrayAlloc(&big_array, big))
    		cout <<"Unable to allocate memory for big array"<<endl;
    		cout <<"Allocated memory for big array"<<endl;
    		for (int i=0;i<big;i++) big_array[i]=0;
    		for (int i=0;i<big;i++) big_array[i]=i;
    		for (int i=0;i<big;i++) cout <<big_array[i]<<endl;
    	return EXIT_SUCCESS;

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