convert for loop into while and do..while

Code:

#include<stdio.h>
int main ()
{
int i,j;

for(i=1;i<=5;i++)  {
  for(j=1;j<=i;j++)
    printf("%i",i);
  printf("\n");
}

return 0;

}

The output is
1
22
333
4444
55555

this is the "for" method, how do i convert it into while and do..while format? i just still noob in programming , any expert help me out pls? thx

 

for ( a ; b ; c ) d;

Is approximately
a;
while ( b ) { d; c; }

 

ya, but if got 2 loops? for(i=0;i<=8;i++) the first loop then inside another for (j=0;j<=i;j++)?

 

So two for loops become two while loops - what's the problem?

 

Code:

int i=1,j=1;

while(i<=5)  {
    printf("%i",i);
    i++;
    while(j<=i)  {
       printf("\n");
       j++;
}

but if i write like this, i compile cant get the correct output same as the for loop
1
22
333
4444
55555

 

Code:

int i=1,j=1;

do {
   printf("%i",i);
   i++;
do {
   printf("\n");
   j++;
}while(j<=i);
}while(i<=5);

 

i don't really get what u really mean.. how about u post the code for me? then i will know better

 

Refer to my other post

Code:

for([COLOR=Red]i=1[/COLOR];[COLOR=Blue]i<=5[/COLOR];[COLOR=Magenta]i++[/COLOR])  {
[COLOR=Lime]  for(j=1;j<=i;j++)
    printf("%i",i);
  printf("\n");[/COLOR]
}

Becomes

Code:

[COLOR=Red]i=1[/COLOR];
while ( [COLOR=Blue]i<=5[/COLOR] ) {
[COLOR=Lime]  for(j=1;j<=i;j++)
    printf("%i",i);
  printf("\n");[/COLOR]
  [COLOR=Magenta]i++[/COLOR];
}

Now apply the same transformation to the inner loop, and you're done.

 

kk, thx so much for the help

 

One thing remember before putting any problem just try to solve atleast one time.

 

If any one putted any silly problem by mistake then that post should be deleted because when we are searching such silly problem making the Image of this forum lower and user time is waisted.