How to compare an address to another address and replaces the value stored in that address? Code: //This program prints the initialize value and the addresses of the //elements inside the array. This proram also allows the user to change //the address of the hardcoded number in the program. #include <stdio.h> #include <conio.h> #include <math.h> #include <stdlib.h> #include <string.h> #define ARRAY_SIZE 4 int main(){ //Declare variable int x=1,rep; char error[128]; // Declare array int arr[]={1,2,3,4}; //Declare pointer int *ptr; system("cls"); //Show value of array elements printf("The value of elements inside the array:\n\n"); for(int i=0;i<ARRAY_SIZE;i++){ printf("Value of element %d: %d\n",i,arr[i]); } //Print addresses of array elements printf("The addresses of elements inside the array:\n\n"); for(int i=0;i<ARRAY_SIZE;i++){ ptr = &arr[i]; printf("Address of element %d: %p\n",i,ptr); } //Show value of variable printf("Value of x: %d\n",x); //Print address of variable ptr=&x; printf("Address of x: %p\n",ptr); This is the part that i really don't know. The user should in put any of the address printed by the program, after inputting the address the program asks the user to change the value stored in that address.. //Input address int temp=0; printf("Please input an address: "); scanf("%d",&temp); *ptr = temp; //Print input printf("Your input: %p\n", *ptr); Code: printf("Please press the spacebar to continue!!"); getche(); system("cls"); do{ system("cls"); printf("Do you want to repeat the computation?\n\n"); printf("1 - Yes\n"); printf("2 - No\n"); scanf("%s",&error); rep=atoi(error); switch(rep){ case 1: main(); break; case 2: break; default: system("cls"); printf("Invalid input. Please try again!!!\n"); printf("Please press the spacebar to continue!!"); getche(); break; } }while(rep>2||rep<1); }
I dont know whether you want to compare the memory location of its value, if you want to compare the address then the pointer variable itself holds the address it points to since it is numerical we can compare directly. if you want to compare based on its value then dereference the pointer and compare with it, I do not know whether I answered your question , If I am wrong please give me more details and please be specific.
Let us just focus on this..:happy: Example: Blues inputted by the user Before: Position Value Address 0 1 0022FEA0 1 2 0022FEA4 2 3 0022FEA8 3 4 0022FEAC Please input an address: 0022FEA0 Please input the new value for the address inputted: 7 After Position Value Address 0 7 0022FEA0 1 2 0022FEA4 2 3 0022FEA8 3 4 0022FEAC Please input an address:
this will help you a little bit. Code: //This program prints the initialize value and the addresses of the //elements inside the array. This proram also allows the user to change //the address of the hardcoded number in the program. #include <stdio.h> #include <conio.h> #include <math.h> #include <stdlib.h> #include <string.h> #define ARRAY_SIZE 4 int main(){ //Declare variable int x=1,rep; char error[128]; // Declare array int arr[]={1,2,3,4}; //Declare pointer int *ptr; [COLOR="Red"]char hexAddress[10]; long int address; int newValue=0;[/COLOR] system("cls"); //Show value of array elements printf("The value of elements inside the array:\n\n"); for(int i=0;i<ARRAY_SIZE;i++){ printf("Value of element %d: %d\n",i,arr[i]); } //Print addresses of array elements printf("The addresses of elements inside the array:\n\n"); for(int i=0;i<ARRAY_SIZE;i++){ ptr = &arr[i]; printf("Address of element %d: %p\n",i,ptr); } [COLOR="Red"]printf("\ngive address:"); fgets(hexAddress,10,stdin); address = strtol (hexAddress,NULL,16); ptr=(int *)(address); printf("value of element at address=%p is =%d\n",ptr,*ptr); printf("\ngive new value:"); scanf("%d",&newValue); *ptr=newValue; printf("value of element at address=%p is =%d\n",ptr,*ptr); for(int i=0;i<ARRAY_SIZE;i++){ printf("Value of element %d: %d\n",i,arr[i]); }[/COLOR] getchar(); getchar(); return 0; }
Thank you!!:happy: but i already resolved the problem.. now may problem is the looping at the last part because when i use switch statement the new value does not appear but when i use if statement the new values print Switch Statement Program Code: #include <stdio.h> #include <conio.h> #include <math.h> #include <stdlib.h> #include <string.h> #define ARRAY_SIZE 4 int main(){ //Declare variable int x=1,rep,i,temp=0; char error[128]; // Declare array int arr[]={2,3,4,5}; //Declare pointer int *ptr; do{ system("cls"); //Show value of variable printf("Value of x: %d\n",x); //Print address of variable ptr=&x; printf("Address of x: %p\n\n",ptr); //Show value of array elements printf("The value of elements inside the array:\n\n"); printf("Position\tElements\tAddresses\n\n"); for(i=0;i<ARRAY_SIZE;i++){ ptr=&arr[i]; printf("%d:\t\t%d\t\t%p\n",i,*ptr,ptr); } //Input address and new value printf("\n"); printf("Please input an address: "); scanf("%x",&ptr); printf("address\n: %X",ptr); printf("Please input the new value: "); scanf("%d",&temp); *ptr=temp; printf("address: %d\n",temp); printf("Please press the spacebar to continue!!"); getche(); while(rep>2||rep<1){ system("cls"); printf("Do you want to repeat the computation?\n\n"); printf("1 - Yes\n"); printf("2 - No\n"); scanf("%s",&error); rep=atoi(error); switch(rep){ case 1: main(); break; case 2: return 0; break; default: system("cls"); printf("Invalid input. Please try again!!!\n"); printf("Please press the spacebar to continue!!"); getche(); break; } } }while(rep==1); } If Statement Program Code: #include <stdio.h> #include <conio.h> #include <math.h> #include <stdlib.h> #include <string.h> #define ARRAY_SIZE 4 int main(){ //Declare variable int x=1,rep,i,q,temp=0; char error[128]; // Declare array int arr[]={2,3,4,5}; //Declare pointer int *ptr; do{ system("cls"); //Show value of variable printf("Value of x: %d\n",x); //Print address of variable ptr=&x; printf("Address of x: %p\n\n",ptr); //Show value of array elements printf("The value of elements inside the array:\n\n"); printf("Position\tElements\tAddresses\n\n"); for(i=0;i<ARRAY_SIZE;i++){ ptr=&arr[i]; printf("%d:\t\t%d\t\t%p\n",i,*ptr,ptr); } //Input address and new value printf("\n"); printf("Please input an address: "); scanf("%x",&ptr); printf("address: %X\n",ptr); printf("Please input the new value: "); scanf("%d",&temp); *ptr=temp; printf("address: %d\n",temp); printf("Please press the spacebar to continue!!"); getche(); while(q!=1){ if(q==2){system("cls"); printf("Input must be either 1 or 2\n");} printf("\n\nReturn to view new list or quit?\n"); printf("\n[1] Return\n[2] Quit\n"); scanf("%d",&rep); if(rep==1)q=1; if(rep==2)return 0; if(rep!=1&&rep!=2)q=2; }//while q!=1 q=0; }while(rep==1); }
Ahh hahaha..now I got it because whenever i choose the number 1 the program resets.. Thanks alot virxen
