have users work experience in database Position Field, Employment Period(from,to) IT Jan 1982 - Feb 1984 Advertizing Mar 1985 - Feb 1990 IT Jan 1990 - May 2002 IT Jan 2007 - Aug 2007 I need to calculate total work experience in IT, Advertizing......... and I need to get values in this vay for example IT- 12.8 it means that 12 years and 8 month in IT.
Fetch all the dates and arrange them in chronological order and then get the time between first and last.
It will no work properly. What if I have IT Jan 1982 - Feb 1985 IT Jan 1983 - May 1986 IT Jan 2001 - Aug 2007 You say 2007-1982=25 but the correct is 10
Look if I have IT Jan 1982 - Feb 1985 IT Jan 1983 - May 1986 1985-1982=3 1986-1983=3 I sum up and get 6. But 4 is correct answer.
But then you are not just add each years that way. His year of work should not overlap as well so you have to make addition like this. 1982 12 months 1983 12 months 1984 12 months 1985 12 months 1986 5 months And this would give you results. You have to b adding months for each year and then see how many months he has actually worked for the whole of his life. This would mean if he is not working for few years that months would also go away.
I need an example. I have already tried different way, but unsuccessfully.:embarasse There are times that some months,years are missed.
Say You have a GRID where each row is a year and each column is a month. Now from 1982 to 1986 loop through all the months and see if that month he was working or not and if he was then assign a flag in the grid. No of flags in the grid is the total number of months he has worked for.
