how will you check the relation of two numbers (greater or lesser) without using Relational operators ?????? :nice::nice:

for comparing u need relational operator na , use if-else.. but the question is without relational operators how will u decide the relation between two numbers....? please

You can do it using the following logic: Let us assume the numbers to be x and y. Code: if(x/y) printf("x is greater"); else printf("y is greater"); Logic: If you divide a smaller number by a greater number the result will be "zero". case 1: x<y (x/y) results "0", in turn makes the condition if(o) => if(false) and so the else part is executed. case 2:x>y (x/y) results some positive value, in turn makes the condition to if(true) and so if part is executed.

hmm.. it's correct good...... but take the worst case , take 'x' and 'y' to be same......... so let us assume x=90 , y=90 , is 90>90 or 90<90 , this statement is false..... so in ur logic , the ur if() will be true for u....... actually it mustt be false......... and my question is for alll operators , and not only fot > & < , also for >= , <= and ==..... and i ll say a clue , in all relational operators only one thing will change entirely, by changing that u can write the logic and check it...... thank u

If the two numbers are same, we can find that out using this XOR condition: Code: if(x^y) printf("Both not equal"); else printf("Both equal"); Logic: If x and y are equal, then condition becomes if(0).

ok you have posted , but i need it in a single condition ......... using a single condition we can check for all numbers....... (>=,<=,>,<) that's i need....