C program without any semicollon

Write a C program without any semicollon (..

 

Code:

int main()
{
    if(printf("Hello World"))
}

 

#include<stdio.h>
#include<conio.h>
void main()
{
if(Printf("C FANATIC"))
getch();
}


by writing above if statement printf() function returns a non zero value
but we have not given any statement under it so it will just print CFANATIC

 

You have a semicolon in getch statement

 

The same coding when written in vi editor of LINUX it will also work without a getch();

 

Doesn't it require a return statement.........????

 

sir(shabbir)
actually getch statement is not compulsory
i have written by mistake
sorry
for inconvemience

 

sir(ASD)

getch is just needed for turbo c compiler usually 3.0
to show us output (i.e.., it has to read a key)
sophisticated compilers need not need that

 

What the Non-Zero value printf() returns ??

 

Actually I am asked "How a C programe can be write without semicolon?"
I think it indicates any processes by which we can capable to code any C programme without using semicollon....

 

hello harit

it actually returns a non zero value (i.e.., TRUE)
but there are no statement under if statement
so it will just print what it is in printf statement

 

what the exact value(non-zero) returned by printf()....?