[C] Play Again Loop Logic

I made a basic calculator using this codes. What i want to learn is how to make a loop after the program ask "try again y/n"? it will return to choose an operation.

Code:

#include<stdio.h>
#include<conio.h>



int main(){
int num1, num2, choice;

printf("Choose an operation\n\n");
printf("[1] Add\n[2] Subtract\n[3] Multiply\n[4] Divide\n[5] Exit\n");
scanf("%d", &choice);

switch(choice){
    
    case 1:
        printf("Enter 1st number:\n");
        scanf("%d", &num1);
        printf("Enter 2nd number:\n");
        scanf("%d", &num2);
        printf("\n%d", (num1+num2));
        break;
    case 2:
        printf("Enter 1st number:\n");
        scanf("%d", &num1);
        printf("Enter 2nd number:\n");
        scanf("%d", &num2);
        printf("\n%d ", (num1-num2));
        break;
    case 3:
        printf("Enter 1st number:\n");
        scanf("%d", &num1);
        printf("Enter 2nd number:\n");
        scanf("%d", &num2);
        printf("\n%d", (num1*num2));
        break;
    case 4:
        printf("Enter 1st number:\n");
        scanf("\n%d", &num1);
        printf("Enter 2nd number:\n");
        scanf("%d", &num2);
        printf("\n%d", (num1/num2));
        break;
    case 5:
         return 0;
        
    default:
        printf("That is not a valid choice.");
        break;
}
getch();
}

 

I would just enclose the lot in a for loop:

Code:

for (int quit=0; !quit; )
{
printf("Choose an operation\n\n");
//...
case 5: quit=1; break;
//...
}