#include<stdio.h> #include<conio.h> int main(){ int a,b; a = -3- -3; b = -3 - - (-3 ); printf("%d %d",a,b); getch(); return 0 ; } the ouput is -6 and 0.Please explain how?
Compiler bug probably. (-3) - (-3)=0 because any finite number minus itself is zero, so if your compiler thinks this is -6 then it's wrong. Similarly (-3) - -(-3) = (-3) - (3) = -6, not 0. The answers are correct though, if transposed, so if the output is 0 -6 then that's correct. -6 0 would be wrong. To make certain, split the output with more detail to be sure: Code: printf("(-3) - (-3) = %d\n",a); printf("(-3) - -(-3) = %d\n",b); Visual Studio 2010 gets the correct answers. Code: void test49() { int a,b; a = -3- -3; b = -3 - - (-3 ); printf("%d %d\n",a,b); printf("-3- -3=%d\n",a); printf("-3 - - (-3 )=%d\n",b); } Output: Code: 0 -6 -3- -3=0 -3 - - (-3 )=-6 The bottom line really is to stop using Turbo C 3.0, since it was written in 1842 by a Japanese caveman who had never seen a computer.
