# 1-dimensional array type double.....and....2-dimensional array

Discussion in 'C++' started by styles8687, Dec 2, 2007.

1. ### styles8687New Member

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ok i have to write two 1-dimensional arrays and one 2-dimensional array, but i was out of town so i have no idea of what im doin. any help i can get with explaining it would be greatly appreciated.

1-dimensional:
write an interactive C++program that asks the user to enter the total rainfall for each of 12 months into a one dimensional array of type double. The program then calculates and displays the total rainfall for the year and the months with the highest and lowest amount. do not accept negative numbers for monthly rainfall...use a loop. if any1 is able 2 explain this 2 me that would b awesome.

2-dimensional:
program should....declare and initialize an array called values, print resultant array, determine and print sum of each row, determine and print sum of each column, determine and print sum of each diagonal. must use loop to accomplish this.

2. ### imported_xpi0t0sNew Member

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How far have you got? Where are you stuck?

3. ### hkp819New Member

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This program takes in the number of rows (n) and columns (m) as well as the elements as a screen input in a matrix n x m.
It then calculates the sum of each row and each column and outputs it using the 'cout' command.
Also, if it is a square matrix, it calculates the sum of diagonal elements and prints it out.

I do not understand clearly your question if you tell for diagonal sum of matrix(2-dimensional array) than program is below....
In this program user enter the row and columns and value of matrix
Than output is sum of diagonal elements.
Code:
```#include <iostream.h>
#include <conio.h>
int main()
{
clrscr();
int A,m,n,x,y,sum=0;
//Create a Matrix A
cout << "Enter number of rows and columns in Matrix A : \n";
cin>>n>>m;
cout << "Enter elements of Matrix A : \n";
for(x=1;x<n+1;++x)
for(y=1;y<m+1;++y)
cin>>A[x][y];
//Find sum of each row
for(x=1;x<n+1;++x)
{
A[x][m+1]=0;
for(y=1;y<m+1;++y)
A[x][m+1]=A[x][m+1]+A[x][y];
}
//Find sum of each column
for(y=1;y<m+1;++y)
{
A[n+1][y]=0;
for(x=1;x<n+1;++x)
A[n+1][y]+=A[x][y];
}
cout << "\nMatrix A, Row Sum (Last Column)" << " and Column Sum (Last Row) : \n";
for(x=1;x<n+1;++x)
{
for(y=1;y<m+2;++y)
cout << A[x][y] << "     ";
cout << "\n";
}
//Print sum of each column
x=n+1;
for(y=1;y<m+1;++y)
cout << A[x][y] << "     ";
cout << "\n";
if(m==n)
{
for(x=1;x<m+1;x++)
for(y=1;y<n+1;y++)
if(x==y)
sum+=A[x][y];
else
if(y==m-(x+1))
sum+=A[x][y];
}
cout << "Sum of diagonal elements is : " << sum << endl;
getch();
return 0;
}```

Input by the user:

3 3
9 8 7 6 5 4 3 2 1

output of that input

Matrix A, Row Sum(Last Column) and Column Sum(Last Row) :
9 8 7 24
6 5 4 15
3 2 1 6
18 15 12
Sum of diagonal elements is : 15