Perfect Squares | 2 Oct 2009

Discussion in '$1 Daily Competition' started by shabbir, Oct 2, 2009.

  1. shabbir

    shabbir Administrator Staff Member

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    Find a,b which satisfy the following

    • a,b are both greater than 1
    • a and b are not equal.
    • a^2 + 3b and b^2 + 3a are perfect square.
    ^ denotes power
     
  2. nimesh

    nimesh New Member

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    a = 11
    b = 16 (or vice versa)

    11 and 16 both are greater than 1
    11 and 16 are not equal

    a^2 + 3b = 11^2 + 3*16 = 121+48 = 169
    b^2 + 3a = 16^2 + 3*11 = 256+33 = 289

    169 and 289 are perfect squares of 13 and 17 resp
     
  3. shabbir

    shabbir Administrator Staff Member

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