hi! my doubt is how unsigned integers store negative numbers?

if i write ,int i=-9 then how -9 is stored in i(8 bit).

if we again print the value in i we won't get -9.but we get some larger number.why it so?

if i write ,int i=-9 then how -9 is stored in i(8 bit).

if we again print the value in i we won't get -9.but we get some larger number.why it so?