simple yet mysterious..

ANUKANNAN's Avatar, Join Date: Jul 2008
Newbie Member
hai everyone..
here is a small code that produced interseting outputs:
guess u all know how this is..ok let me not beat abt the bush..
main()
{
float i=1.1;
double j=1.1;
if(i==j)
cout<<"hai";
else
cout<<"bye";
}if u give i=1.0 or 1.5 the output is hai
else it's bye y is that so?if u know the reason then am lucky..
0
shabbir's Avatar, Join Date: Jul 2004
Go4Expert Founder
First thing first. Try having the thread in the right forum for better response.

Now about your query the comparison is done based on float and double and so check with the same data type and see what happens or else have a type cast.
0
xpi0t0s's Avatar, Join Date: Aug 2004
Mentor
The explanation is not an easy one to give but you may be able to work it out.

1.0 and 1.5 work fine. What about 1.25, 1.125, 1.0625, 1.03125? You may be able to think of others in this sequence.
What are the above numbers in binary? E.g. 1.0_10=1.0_2. 1.5_10=1.1_2. 1.25_10=1.01_2 (_10 and _2 mean "base 10" and "base 2").
What are the binary representations of the numbers where the equality test fails, (a) in float precision; (b) in double precision?
What if i and j could store decimal numbers exactly, and, say, i=1.333 and j=1.333333. Should the test i==j return TRUE or FALSE?

By working through the above you'll learn a heck of a lot more than if I just gave you the answer directly.