make a query with the value of text

guif's Avatar
Go4Expert Member
hi!

I have problems to give the value of a text.

I have in a PHP this:

Code:
<?php
$searchq  = strip_tags($_GET['q']);
$getRecord_sql = 'select pkey from jiraissue where project = 10040 and pkey like "%'.$searchq.'%"';
$getRecord = mysql_query($getRecord_sql);
if(strlen($searchq)>0){
echo '<ul>';
while ($row = mysql_fetch_array($getRecord)) {
?>
    <li><a href="lib/consultas.php?accion=E" onclick="load('lib/consultas.php?accion=E','consulta');return false;">
and in my file consultas.php, the case E:

Code:
case 'E':		
$queEmp	= "select pkey, created, UPDATED, reporter, assignee, summary, description from `jiraissue` where project = 10040 and pkey like ".$search-q2." ";  
$resEmp = mysql_query($queEmp, $conexion) or die(mysql_error());
$totEmp = mysql_num_rows($resEmp);
if ($totEmp> 0) {
	while ($rowEmp = mysql_fetch_assoc($resEmp)) {
		echo "<strong>Incidencia:</strong> <u>".$rowEmp['pkey']."</u><br>";
		echo "<strong>Data:</strong> ".$rowEmp['created']." / ".$rowEmp['UPDATED']."<br>";		
		echo "<strong>Tecnic Obre:</strong> ".$rowEmp['reporter']."<br>";
		echo "<strong>Tecnic Actual:</strong> ".$rowEmp['assignee']."<br>";
		echo "<strong>Descripcio incidencia:</strong> ".$rowEmp['summary']."<br>";
		echo "<strong>Intervencions:</strong> ".$rowEmp['description']."<br><br>";
		}
	}
break;	
mysql_close($conexion);

Why the result of my query is:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '0' at line 1
0
pradeep's Avatar, Join Date: Apr 2005
Team Leader
Code: PHP
// This line
$queEmp = "select pkey, created, UPDATED, reporter, assignee, summary, description from `jiraissue` where project = 10040 and pkey like ".$search-q2." "
// Should be
$queEmp = "select pkey, created, UPDATED, reporter, assignee, summary, description from `jiraissue` where project = 10040 and pkey like '".$search-q2."'";
0
guif's Avatar
Go4Expert Member
no... not's run.
Is it possible with php read the variable of another file?

I put all my code:

this is the text box into a index.php:

Code:
<input name="search-q2" id="search-q2" type="text" onkeyup="javascript:autosuggest2()"/>
and into the consultas.php, the case E:

Code:
case 'E':		
	
$queEmp	= "select `pkey`, `created`, `UPDATED`, `reporter`, `assignee`, `summary`, `description` from `jiraissue` where project = 10040 and `pkey` like ???VARIABLE????   ";		
$resEmp = mysql_query($queEmp, $conexion) or die(mysql_error());
$totEmp = mysql_num_rows($resEmp);
if ($totEmp> 0) {	
	while ($rowEmp = mysql_fetch_assoc($resEmp)) {
		echo "<strong>Incidencia:</strong> <u>".$rowEmp['pkey']."</u><br>";
		echo "<strong>Data:</strong> ".$rowEmp['created']." / ".$rowEmp['UPDATED']."<br>";		
		echo "<strong>Tecnic Obre:</strong> ".$rowEmp['reporter']."<br>";
		echo "<strong>Tecnic Actual:</strong> ".$rowEmp['assignee']."<br>";
		echo "<strong>Descripcio incidencia:</strong> ".$rowEmp['summary']."<br>";
		echo "<strong>Intervencions:</strong> ".$rowEmp['description']."<br><br>";
	}
}
break;	
mysql_close($conexion);
and I have a Framework:

Code:
function autosuggest1() {
q = document.getElementById('search-q2').value;
// Set te random number to add to URL request
nocache = Math.random();
http.open('get', 'lib/search_incidencias.php?q='+q+'&nocache = '+nocache);
http.onreadystatechange = autosuggestReply;
http.send(null);
}

function autosuggestReply() {
if(http.readyState == 4){
	var response = http.responseText;
	e = document.getElementById('results');
	if(response!=""){
		e.innerHTML=response;
		e.style.display="block";
	} else {
		e.style.display="none";
	}
}
}
and, search_incidencias.php:

Code:
<?php
$searchq		=	strip_tags($_GET['q']);
$getRecord_sql = 'SELECT `pkey` FROM `jiraissue` WHERE project = "10040" and `pkey` LIKE "%'.$searchq.'%"';
$getRecord		=	mysql_query($getRecord_sql);
if(strlen($searchq)>0){
echo '<ul>';
while ($row = mysql_fetch_array($getRecord)) {
?>
	<li><a href="lib/consultas.php?accion=E" onclick="load('lib/consultas.php?accion=E','consulta');return false;">
<?php 
echo $row['pkey']; 
?>

here is all my code...
0
pradeep's Avatar, Join Date: Apr 2005
Team Leader
Code: PHP
// This line
$queEmp = "select pkey, created, UPDATED, reporter, assignee, summary, description from `jiraissue` where project = 10040 and pkey like ".$search-q2." "
// Should be
$queEmp = "select pkey, created, UPDATED, reporter, assignee, summary, description from `jiraissue` where project = 10040 and pkey like '".$search-q2."'";
0
guif's Avatar
Go4Expert Member
If I put echo $search-q2; the result is 0.
And, If I put echo $queEmp; i see a white page without results.

With PHP is possible to give a variable of another PHP file?
0
pradeep's Avatar, Join Date: Apr 2005
Team Leader
$search-q2 is an invalid variable name '-' is not a valid character for variables, try usinh '_' instead.
0
guif's Avatar
Go4Expert Member
I change it. I put search_q2.
and.. I insert: echo search_q2;. The result of echo: search_q2!!!!
why?
0
pradeep's Avatar, Join Date: Apr 2005
Team Leader
echo $search_q2; ??
0
guif's Avatar
Go4Expert Member
sorry. I put echo $search_q2;.
The result is a white page without results.
0
pradeep's Avatar, Join Date: Apr 2005
Team Leader
In your code I see that you have defined $searchq and you are using $search_q