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program to implement post fix evaluation in the given code using C

Discussion in 'C' started by mananarts, Jul 9, 2010.

  1. mananarts

    mananarts New Member

    without changing the main function i need to write the program as described above in subject line. the algoritham to be follwed is also given at last of this forum.

    Can anyone give me the exact solution to it


    #include <stdio.h>
    #include <stdlib.h>
    #include <crtdbg.h>

    //#include "stack_int.h"

    int evalExp( int exp[], int size );

    int main ( void )
    int expList[][35] =
    {25, 7, '*', 14, '-', 6, '+'},
    {1, 24, 3, '+', '*', 41, '-'},
    {2, 37, 4, '+', '*', 15, '-'},
    {8, 30, 9, '-', 6, '/', '+', 4, '*'}
    int i;

    printf( "\nLAB 3: STACKS\n\n"
    "This program is a test driver for Problem 15, Page 142,\n"
    "that evaluates postfix expressions.\n\n" );
    for( i = 0; i < 4; i++ )
    printf ("%d\n", evalExp(expList, sizeof expList/sizeof(int)));

    printf( _CrtDumpMemoryLeaks() ? "Memory Leak\n" : "No Leak\n");

    return 0;

    /* =============================================
    Evalute a postfix expression
    Pre: exp - contains the expression
    size - number of elements in the expression
    Return: the value of the expression

    int evalExp( int exp[], int size )
    return 0;

    create Stack
    loop ( for each character)
    if (its opearand )
    push stack ( stack, character)
    popStack ( stack.op2)
    popStack (stack, op1)
    operator = character
    set value to calculate ( op1,operator, op2)
    pushStack (stack,value)
    end if
    end loop
    popStack (Stack,Result)
    return (result)
    end postFixEvaluate
  2. xpi0t0s

    xpi0t0s Mentor

    The idea of these exercises is that you learn by programming. You don't learn anything by studying complete samples, otherwise that's what the teacher would have given you in the first place.

    Seems the code has mostly been written for you, leaving you with very little to do except change the algorithm syntaax into C, for example "loop (for each character)" might translate to something like
    for (int i=0; i<size; i++)
      // ... exp[i] ...
    So where exactly are you stuck?

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