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Discussion in 'C' started by blade, Sep 15, 2010.

  1. blade

    blade New Member

    Please give the program code of this problems:

    1. Enter a number (x) and get the average of all numbers from 1 to x.
    2. Enter a number (x) and print the factorial of the number.
    Program will look like this:
    Enter value: 4
    4 24
    -Exit when the value entered is zero (0).
    factorial = (n)*(n-1)*(n-2)
    ex: 4!=4*3*2*1

    * I dont have any clue on number 2 on how to do it.
    *This two numbers need a loop (for).
    * I tried number 1 but it's not right, anyway here is the program code i did:
    #include <stdio.h> 
    #include <conio.h> 
    int main() 
    int x,y; 
    float z; 
    printf ("\nEnter a number:\t"); 
    scanf ("%d",&x); 
    for (y=z;y>0;y--); 
    printf ("\n\nThe average of all numbers from 1 to %d is %f",x,z); 

    *THANKS in advance.
    Last edited by a moderator: Sep 16, 2010
  2. virxen

    virxen New Member

    exercise 1

    #include <stdio.h>
    int main(){
        int x[COLOR=Red]=0[/COLOR],y[COLOR=Red]=0[/COLOR];
        float z[COLOR=Red]=0[/COLOR];[COLOR=Red]//always initialize variables in the beginning[/COLOR]
        [COLOR=Red]while (x<=0){//number must be greater or equal to 1[/COLOR]
            printf ("\nEnter a number:\t");
            scanf ("%d",&x);[COLOR=Red]getchar();//always after a scanf[/COLOR]
        [COLOR=Red]for (y=1;y<=x;y++)
            z+=y;//use the for loop from 1 to given number,store the total sum of these numbers in z[/COLOR]
        [COLOR=Red]z/=x;//after exiting the loop divide result with total numbers[/COLOR]
        printf ("\n\nThe average of all numbers from 1 to %d is %f",x,z);
        return 0;
    blade likes this.
  3. blade

    blade New Member

  4. virxen

    virxen New Member

    for the factorial send the code you tried to help you.

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