Pointer to function

theimmortalbg's Avatar, Join Date: Jan 2011
Newbie Member
hello this is my program

Code:
#include "stdafx.h"
#include <iostream>
using namespace std;

bool isOdd(const int* item)
{
return (*item)%2;
}

int deleteItems (int *array, int itemSize, int itemsCount, bool (*shouldDeleteItem)(const int*))
{
for(int i=0; i<itemsCount; i++)
cout<< shouldDeleteItem (array+i)<< endl;	

return itemsCount*itemSize; 
}

void main()
{
int *p = NULL;
int n;
cout<< "Enter length of array: ";
cin>> n;
p = new int [n];

cout<< "Numbers in the array: ";
for(int i=0; i<n; i++)
cin>> *(p+i);

for(int i=0; i<n; i++)
{
deleteItems(p, sizeof(p+i), n, isOdd(p+i));
}	
}
I am trying to call the function deleteItems(int *array, int itemSize, int itemsCount, bool (*shouldDeleteItem)(const int*)) but i can't. Compiler says cannot convert parameter 4 from bool to bool(_cdecl*)(const int *). How i can call delleteItems with last parameter isOdd(p+i). Thanks

Last edited by shabbir; 23Jan2011 at 18:46.. Reason: Code blocks
0
jimblumberg's Avatar
Ambitious contributor
You should just be passing the function pointer like:
Code:
deleteItems(p, sizeof(p+i), n, isOdd)


Jim