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Passing a two dimensional array to a function

Discussion in 'C' started by bashamsc, Dec 18, 2007.

  1. bashamsc

    bashamsc New Member

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    I tried two methods for this and it worked.

    First Method :

    Code:
    #include<stdio.h>
    
    void fun(int *a,int col , int row)
    {
    int i,j;
    for(i=0;i<3;i++)
    {
    for(j=0;j<4;j++)
    {
    printf(" %d\n",*(a+j));
    }
    a=a+4;
    }
    }
    
    
    main()
    {
    
    int arr[4][3] = {{1,2,3},{4,5,6},{7,8,9},{10,11,12}};
    
    fun(&arr[0][0],3,4);
    
    }
    

    Second Method :

    Code:
    #include<stdio.h>
    
    void fun(int a[3][3],int col , int row)
    {
    int i,j;
    for(i=0;i<3;i++)
    {
    for(j=0;j<3;j++)
    {
    printf(" %d\t",a[i][j]);
    }
    printf("\n\n");
    }
    }
    
    
    main()
    {
    
    int arr[3][3] = {{1,2,3},
                     {4,5,6},
                     {7,8,9}};
    printf("%u\n",arr);
    fun(arr,3,3);
    
    }
    
     
    Last edited by a moderator: Dec 18, 2007
  2. kv.santosh

    kv.santosh New Member

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    Hi,

    just a small correction...ur function should rather used passed row an col values insetad of hardcoding them...somehting like this....

    Code:
    void fun(int *a,int col , int row)
    {
    int i,j;
    for(i=0;i<col ;i++)
    {
    for(j=0;j<row;j++)
    {
    printf(" %d\n",*(a+j));
    }
    a=a+row;
    }
    }
     
    Last edited by a moderator: Dec 18, 2007
  3. shabbir

    shabbir Administrator Staff Member

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  4. Salem

    Salem New Member

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    Please don't PM me for 1:1 support.
    Learning how to indent code as well would be a priority as well.

    In response to "method 1".
    http://c-faq.com/aryptr/ary2dfunc2.html

    > I tried two methods for this and it worked.
    Be careful of thinking that "works for me" is any substitute for knowing what is guaranteed by the standard. There are hundreds (possibly thousands) of compilers out there, and you've just tested one of them with a single experiment.
     

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