[boygenius]

i have created an image gallery using php.
everything if fine except that the links to the full images are not working.
www.nitesh.x10hosting.com/gallery.php
the thumbnails are linked to the full image , however this does not work as expected.

[shabbir]

Your images are linked to gallery.php?album_name=illusions&max=10 and so they don't show complete images when gallery.php shows with the above parameter

[boygenius]

i changed the links of some of the images to absolute ones(see gallery illusion) , but even that did not work.
the problem seems to be something else as when i put a "image" link on that page to one of the images it worked fine,but the thumbnails do not link.
one more thing i would like to add is that the links work fine in IE6 and OPERA but not in firefox and safari

[shabbir]

There is definitely some problem in your code and if you share that we may be able to help

[boygenius]

here's the portion of the code(gallery.php) that generates the images and links

PHP Code:

if(!$_GET['album_name'])
{}
else
{
        $album_name=$_GET['album_name'];
        $max=$_GET['max'];
        if(!isset($_GET['pic_num'])) $_GET['pic_num']=0;
        $pic_num=$_GET['pic_num']; 
          
        require('db_login_details.php');
          
        $connection=mysql_connect($db_hostname, $db_username, $db_password);
        if(!$connection)
        die("Failed to connect to database".mysql_error());
        
        
// for previous        
        if(!$pic_num)
        $previous="#nogo";
        else
        {$temp=$pic_num-9;
        $previous="gallery.php?album_name=$album_name&pic_num=".$temp."&max=$max" ;
        }
        
        $query="SELECT pic_num,pic_name,pic_thumb,pic_full,pic_size,pic_desc FROM wizkid_mysite.gallery_$album_name where pic_num > '$pic_num'";
//          echo"\n<br/>pic_num = $pic_num <br/>$query";
         $query_result=mysql_query($query);
         echo"\n<div class=\"gallery\"><ul>";
         if(!$query_result)
         {
         die("<br/>table ".mysql_error());
         }
         
         $i=0;
         while(($row=mysql_fetch_row(($query_result)))&&($i++<9))
         {
             echo"\n<li>
                \n 
                \n<a href=\"$row[3]\">
                \n<img src=\"$row[2]\" width=\"100px\" height=\"100px\" alt=\"$row[5]\"/>
                \n</a>
                \n</li> ";
            $for_next=$row[0];
            
                
         }
//         if(!($row=mysql_fetch_row(($query_result)))&&$i++<9)
            while(($i)%3!=0)
            {
             $i++;
             echo"\n<li style=\"visibility:hidden;\"><a><img></a></li>";    
            }
         echo"\n</ul></div>";
 // for  next
//    echo"<br/>for_next= $for_next max=$max<br/>";
    if($for_next<$max)
    $next=htmlentities($_SERVER['PHP_SELF'])."?album_name=$album_name&pic_num=$for_next&max=$max";
    else
    $next="#nogo";
        echo"\n<br/><p class=\"album_nav\">
             \n<a href=\"".$previous."\">previous</a>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;\n<a href=\"".$next."\">next</a>             
            \n<a href=\"".htmlentities($_SERVER['PHP_SELF'])."\">Change ALbum</a>
            \n</p>";
            mysql_close($connection);
             
} 


[shabbir]

There are lots of error like <a><img></a>

You should see how to display the image

Apart from that code you don't have the img tag to display full image