#include <stdio.h>
main()
{
char a[5] = "abcd";
int b = 3;
printf("%c\n",a[b]);
printf("%c\n",((char *) b)[(int) a]);
}
i get d d as output..
a[3] = d..i get it..
what ((char *)b)[(int) a] doing there...
all i can understand from the above is that it is doing something that is producing lyk i[a] from a[i] type..
wats happening der actually n how is it happening???
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Mentor
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| 28Nov2012,03:01 | #2 |
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It's casting b, which is an integer, to a char*, then casting a, which is an array but taken as a char* in this context, to an integer, then using pointer[offset] syntax to address the 'd'.
pointer[offset] is just worked out as pointer+offset*sizeof(*pointer) so there's no difference between a[b] and b[a], providing b and a in the latter case are cast correctly. |
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Go4Expert Member
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| 12Dec2012,02:20 | #3 |
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Thank u..
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