Help me

Sum of even digits:

Code:

#include <stdio.h>

void even(int num)
{
  int index, num, sum = 0;
  for(index = 0; index <= num; index += 2)
    if(num % 2 == 0)
      sum += 1;
      printf("The sum of even numbers is: %d", sum);
}

void main()
{
    int num;
    clrscr();
 
    printf("\nEnter Number: ");
    scanf("%d", &num);

    even(num);

    getch();
}

what wrong in this code. the answer is always 0 what is the correct program to get this sample run:

Enter number: 12345
Even Number: 6

please help me

 

Code:

#include<stdio.h>
#include<conio.h>
#include<math.h>
void even(int num,int p)
{
 int index,sum=0,r,s,q;
 s=p;
for(index=1;index<=s;index++,p--)
{
r=num/pow(10,(p-1));
q=num-r*pow(10,(p-1));
num=q;
if(index%2==0)
{
sum+=r;
}
}

printf("%d",sum);
}
void main()
{
int num,c,p=0;
clrscr();
printf("Enter number");
scanf("%d",&num);
c=num;
while(c>0)
{
c=c/10;
p++;
}
even(num,p);
getch();
}