# converting to 32 bit long form

Discussion in 'C' started by arvind_khadri, Nov 16, 2007.

1. ### arvind_khadriNew Member

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hi...hey guys i just wanted a help on this....how do i convert a given number to a 32 bit long form...plz help....

2. ### SalemNew Member

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Do you have any examples of what you're trying to accomplish?

3. ### arvind_khadriNew Member

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if i enter 153.18.8.105 the o/p should be 2568095849....for separation u can use strtok for separating.....

4. ### SalemNew Member

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Use strtol().
One of the things it returns is a pointer to where it got to (ie, the dots between numbers).
This you use to locate the start of the next number.

5. ### arvind_khadriNew Member

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well salem i got tat part...but the next thing is how do i convert...tats wat am nt able to get...so i needed help on it.....

6. ### SalemNew Member

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You mean that
2568095849 is (153 << 24) + (18 << 16) + (8 << 8) + 105

It's just a loop, with a shift and and add.

7. ### arvind_khadriNew Member

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thanks for tat...well so rt nw u mean to say tat find the binary eqvt and keep shifting and then concatenate the thing to find final result??if u could post the code here it would be really very helpful of u...

8. ### arvind_khadriNew Member

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i wasnt able to sihft it...whenver i giver 153<<24 it shows 0 as o/p....

9. ### SalemNew Member

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Well it would do, if you were storing the result in an unsigned char say. All the bits fell off the end!

It needs to be in an unsigned long before you shift it left 24 bits.

10. ### arvind_khadriNew Member

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i could get the following code...but cant understand how it works.....can u pls explain it....
code:cpp

Code:
```#include<string.h>
#include<conio.h>
#include<stdio.h>
#include<math.h>
{
unsigned long int a;
} e;
void main()
{
char ip[100];
char *p;
int i,n,j,po;
unsigned long int d;
e.a=0;
clrscr();
printf("\nenter the ip");
scanf("%s",ip);
p=strtok(ip,".");
n=strlen(p) ;
d=0;
po=0;
for(i=n-1;i>=0;i--)
{
d=d+(*(p+i)-48)*pow(10,po);
po++;
}
e.a=d*pow(256,3);
for(j=2;j>=0;j--)
{
p=strtok(NULL,".");
n=strlen(p);
d=0;
po=0;
for(i=n-1;i>=0;i--)
{
d=d+(*(p+i)-48)*pow(10,po);
po++;
}
e.a=e.a+d*pow(256,j);
}
printf("\n the ip add is :%lu",e.a);
getch();
}```

Last edited by a moderator: Nov 18, 2007
11. ### SalemNew Member

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Please don't PM me for 1:1 support.
I could, but I'm not interested in reading code which has been posted without using code tags.

12. ### shabbirAdministratorStaff Member

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arvind_khadri, Learn to post code in the posts with the code block

13. ### arvind_khadriNew Member

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shabbir thanks for the code block....
now its in code block...now pls help me....

14. ### SalemNew Member

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Sure, there are lots of things wrong with it.

> void main()
http://c-faq.com/ansi/voidmain.html

> #include<conio.h>
This is a non-standard header file, so you should avoid using unless necessary.
It is also obsolete as well, as no new compiler will ever have such a thing. Even compilers like dev-c++ which do include it do only for backward compatibility.