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How to convert a number between 0-9 to Char

Discussion in 'C' started by Musab, Jul 14, 2008.

  1. Musab

    Musab New Member

    Hello again :)

    I'm generating a random number between 0 and 9
    I want to assign that number to a character so I can store it in a character array;

    something like
    if i = 3
    c = '3';

    if i =4
    c = '4'

    but smarter way :sosp:
  2. shabbir

    shabbir Administrator Staff Member

    Directly assigning should do the job for you.

    char c = i;
  3. akhanna01

    akhanna01 New Member

    add the ascii value to it................
  4. xpi0t0s

    xpi0t0s Mentor

    if (i>=0 && i<=9) c=i+'0';
    Or just generate random numbers between '0' and '9'.
  5. Musab

    Musab New Member

    Thanks for the tip...yes rand()%10 + '0' works
  6. aali

    aali New Member

    use dynamic cast
    for example
    int a;
    char b;
  7. xpi0t0s

    xpi0t0s Mentor

    yes, but will that convert 0x00000000 to '0', which is what the OP wanted, or will it convert it to 0x00?

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