C Preprocessor problem

Hi,
I have a piece of code as pasted below.

I get warnings like

test1.c:29:32: warning: pasting "(" and ""ERROR:"" does not give a valid preprocessing token
test1.c: In function `main':
test1.c:29: `__MODULE__' undeclared (first use in this function)
test1.c:29: (Each undeclared identifier is reported only once
test1.c:29: for each function it appears in.)

What does warning: pasting "(" and ""ERROR:"" does not give a valid preprocessing token mean?

And where is __MODULE__ defined?

Please provide me some solution.
Thanks,
Taklu.

--------------------------------------------------------

Code:

#include <stdio.h>
#include <stdarg.h>

#define DL1 "%s:"
#define DR1 ,__MODULE__
#define DL2 "%d:"
#define DR2 ,__LINE__


void Trace(char *format, ...);

#define Debug(ARGS...) Trace(##ARGS)


#define Error(ARGS,...)   \
        Debug("ERROR:"DL1 DL2 ARGS "\n" DR1 DR2, ## __VA_ARGS__)


void Trace(char *format, ...){
	va_list args;
    va_start(args, format);
	vprintf(format, args);
	va_end(args);
	return;
}

main(){
	int i = 10;
	Error("Print from main");
	return 0;
}

 

Well there's some serious preprocessor abuse going on here...
You define Debug() as Trace, then Error as Debug, so Error is actually being defined as Trace().
When you use the ## pasting token, you need to provide two tokens to paste together, so Trace (##ARGS) makes no sense, and neither does DR2, ##__VA_ARGS__ a few lines later.
So possibly this is old code that worked on older compilers and needs fixing up for new compilers.
__MODULE__ and __LINE__ are defined by the preprocessor; __MODULE__ is the filename and __LINE__ is the current line number.