You have a custom operation ^ and the following equation x ^ y = 2x + y,
Now what is the value of a in 2 ^ a = a ^ 3
BTW I also don't know the answer and is a question of some paper.
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Pro contributor
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| 20Nov2009,20:29 | #2 |
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a=1
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Go4Expert Founder
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| 21Nov2009,10:59 | #3 |
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Would you explain the answer
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Skilled contributor
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| 21Nov2009,11:22 | #4 |
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x^y = 2x +y
2^a = a^3 ======================= 2^a = 2(2)+a 2^a = 4+a ================= a^3 = 2(a)+3 =============== 4+a = 2a+3 2a-a=4-3 a=1 |
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Pro contributor
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| 21Nov2009,12:20 | #5 |
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Quote:
Originally Posted by sameer_havakajoka |
