hi.....fellow pfogrammers!.....my name is shiva harrinanan and i'm a first year computer science student at uwi....i'm a bit green with respect to this field but its an interesting field and i really want to become part of it.....
Re: hi.....programmers!......need some help below Code: #include<stdlib.h> #include<stdio.h> #include<string.h> struct Student { char sId[10]; // student ID char fName[30]; // student's first name char lName[30]; // student's last name int m, p, c; // m = maths, p = physics, c = chemistry // m, p, and c belong to the range [0..10] double avg; //average mark with 1 digit after decimal point }; //--------------------------------------------------------- Student input1Student(); void output1Student(const Student &x); void inputStudentList(Student list[], int &n); void outputStudentList(const Student list[], const int &n); //--------------------------------------------------------- int main(void) { int op = 0, op2 = 0; int n = 0; Student list[10]; while(op != 8) { printf("1. Input student list\n"); printf("2. Output student list\n"); printf("3. Add a new student\n"); printf("4. Search a student by Id or last name\n"); printf("5. Delete a student with a given student Id\n"); printf("6. Update a student with a given student Id\n"); printf("7. Sort on last name or average mark\n"); printf("8. Exit\n"); printf("Enter your option (1-8): "); scanf("%d", &op); switch(op) { case 1: inputStudentList(list, n); break; case 2: outputStudentList(list, n); break; case 3: break; case 4: printf("\t1. Search by Id\n"); printf("\t2. Search by last name\n"); printf("Select an option (1 or 2): "); scanf("%d", &op2); break; case 5: break; case 6: break; case 7: printf("\t1. Sort on last name\n"); printf("\t2. Sort on average mark\n"); printf("Select an option (1 or 2): "); scanf("%d", &op2); break; } } // while(op != 8) //system("pause"); return 0; } //--------------------------------------------------------- Student input1Student() { Student x; printf("Student ID: "); scanf("%s", x.sId); fflush(stdin); // clear '\n' in buffer printf("First name : "); fgets(x.fName, 80, stdin); x.fName[strlen(x.fName) - 1] = '\0'; printf("Last name : "); fgets(x.lName, 80, stdin); x.lName[strlen(x.lName) - 1] = '\0'; printf("Maths : "); scanf("%d", &x.m); printf("Physics : "); scanf("%d", &x.p); printf("Chemistry : "); scanf("%d", &x.c); fflush(stdin); // clear '\n' in buffer x.avg = (double)(x.m + x.p + x.c) / 3; printf("------------------------------\n"); return x; } //--------------------------------------------------------- void output1Student(const Student &x) { printf("Student ID : %s\n", x.sId); printf("First name : %s\n", x.fName); printf("Last name : %s\n", x.lName); printf("Maths : %d\n", x.m); printf("Physics : %d\n", x.p); printf("Chemistry : %d\n", x.c); printf("Average mark : %.2f\n", x.avg); printf("------------------------------\n"); } //--------------------------------------------------------- void inputStudentList(Student list[], int &n) { int i = 0; printf("Enter the number of students : "); scanf("%d", &n); for (i = 0; i < n; i++) list[i] = input1Student(); } //--------------------------------------------------------- void outputStudentList(const Student list[], const int &n) { int i = 0; for (i = 0; i < n; i++) output1Student(list[i]); }
basically i wanna write a simple C program of student management system using an array of structures...it suppose to give the user some options but as you can see, i'm fresh out of ideas...any input will be deeply appreciated...thanks