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C++ error C4716: 'F_Ite' : must return a value

Discussion in 'Meet and Greet' started by sdmahapatra, Jun 16, 2009.

  1. sdmahapatra

    sdmahapatra New Member

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    Hi all,I am a new coder in C++ and have found "error C4716: 'F_Ite' : must return a value".
    I want to return all the value of a,b,c,Fc,Fd to the main function at each iteration at a time.
    But in general we return only return one value.please help me to fulfill this coding.

    Thanks

    Code:
    double F_Ite()
     {                      //F_Ite Function Start   
         //Locally Data_type Declaration And Initialization :
      int numElement =20;
      double *a,*b,*c,*d,*Fc,*Fd;
      a = new double[numElement];
      b = new double[numElement];
      c = new double[numElement];
      d = new double[numElement];
      Fc= new double[numElement];
      Fd= new double[numElement];
         
      
      for(int k=1;k<(NI-1);k++)
        {                        //Main 'for' Loop Start
            std::cout <<"\n";
            system("pause");
            std::cout <<"\n";
            std::cout <<"At The "<<k+1<<" Iteration :\n";
            
          if(Fc[k]<Fd[k])
          {                     //Outer 'if' Start
            a[k+1]=a[k];
            std::cout <<"The Value Of a" << k+1 << "=" << a[k+1] << "\n";
            b[k+1]=d[k];
            std::cout <<"The Value Of b" << k+1 << "=" << b[k+1] << "\n";
            //c[k+1]=b[k+1]-(0.618034*((1-pow(-0.381966,NI-k))/(1-pow(-0.381966,NI-k+1))))*(b[k+1]-a[k+1]);
            //cout <<"The Value Of c" << k+1 << "=" << c[k+1] << "\n";
            if(k==(NI-1))
            {
              c[k+1]=c[k+1]+z;
              std::cout <<"The Value Of c" << k+1 << "=" << c[k+1] << "\n";
            }
            else
            {
            c[k+1]=b[k+1]-(0.618034*((1-pow(-0.381966,NI-k))/(1-pow(-0.381966,NI-k+1))))*(b[k+1]-a[k+1]);
            std::cout <<"The Value Of c" << k+1 << "=" << c[k+1] << "\n";
            }
            d[k+1]=c[k];
            std::cout <<"The Value Of d" << k+1 << "=" << d[k+1] << "\n";
    
            Fc[k+1]=(exp(-c[k+1]))+(c[k+1]*c[k+1]);
            std::cout <<"The Value Of Fc" << k+1 << "=" << Fc[k+1] << "\n";
            //std::cout <<"The Value Of Fc" << k+1 << "=" << Fc[k] << "\n";
    
            Fd[k+1]=Fc[k];
            //std::cout <<"The Value Of Fd" << k+1 << "=" << Fc[k] << "\n";
            std::cout <<"The Value Of Fd" << k+1 << "=" << Fd[k+1] << "\n";
                    
    
          }                        //Outer 'if' Close
           else
          {                     //Outer 'else' Start
            a[k+1]=c[k];
            std::cout <<"The Value Of a" << k+1 << "=" << a[k+1] << "\n";
            b[k+1]=b[k];
            std::cout <<"The Value Of b" << k+1 << "=" << b[k+1] << "\n";
            c[k+1]=d[k];
            std::cout <<"The Value Of c" << k+1 << "=" << c[k+1] << "\n";
            //d[k+1]=a[k+1]+((0.618034)*((1-pow((-0.381966),(NI-k)))/(1-pow((-0.381966),(NI-k+1)))))*(b[k+1]-a[k+1]);
            //std::cout <<"The Value Of d" << k+1 << "=" << d[k+1] << "\n";
            
            if(k==(NI-1))
          {
            d[k+1]=d[k+1]+z;
            std::cout <<"The Value Of d" << k+1 << "=" << d[k+1] << "\n";
          }
    
            else
            {
            d[k+1]=a[k+1]+((0.618034)*((1-pow((-0.381966),(NI-k)))/(1-pow((-0.381966),(NI-k+1)))))*(b[k+1]-a[k+1]);
            std::cout <<"The Value Of d" << k+1 << "=" << d[k+1] << "\n";
            }
    
                
            Fc[k+1]=Fd[k];
            //std::cout <<"The Value Of Fc" << k+1 << "=" << Fd[k] << "\n";
            std::cout <<"The Value Of Fc" << k+1 << "=" << Fc[k+1] << "\n";
            Fd[k+1]=(exp(-d[k+1]))+(d[k+1]*d[k+1]);
            std::cout <<"The Value Of Fd" << k+1 << "=" << Fd[k+1] << "\n";
            //std::cout <<"The Value Of Fd" << k+1 << "=" << Fd[k] << "\n";
    
          }                        //Outer 'else' Close
         }                    //Main 'for' Loop Close
    
          //Another 'if' Condition Start But Within The 'for' Loop
            if(Fc[10]<Fd[10])
        {
            std::cout <<"\n";
          std::cout <<"\nAt Final Iteration :\n";
          a[NI]=a[NI-1];
          b[NI]=d[NI-1];
          std::cout <<"The Value Of a11 =" << a[NI] << "\n";
          std::cout <<"The Value Of b11 =" << b[NI] << "\n";
        }
        else
        {
          a[NI]=c[NI-1];
          b[NI]=b[NI-1];
          std::cout <<"The Value Of a11 =" << a[NI] << "\n";
          std::cout <<"The Value Of b11 =" << b[NI] << "\n";
        }
    
    }                   //F_Ite Function End
    
     
    Last edited by a moderator: Jun 16, 2009

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