I need your help

hello guys

this is my first post in here, I hope you will help me guys


I tried many time but I couldn't get the required pattern


write a c program to generate the
pattern shown using nested for loop

1
01
101
0101


and



0
12
345
6789

 

I think this is your home work . Try by your own . If you struck any where then post here .

 

Take it step by step try to find some 'pattern' that is there in the output.Try to from a logic on how you could print that than put something over here.Its not that difficult but try yourself.

 

this will give you the opposite from what you want in 1)
do the rest by yourself

(hint:you must add 1 char and 1 number in order to work as you want...but where?)

Code:

#include <stdio.h>

int main(){
    for (int i=0;i<4;i++){
        printf("\n");
        for (int j=0;j<(i+1);j++)
            printf("%d",(i+j)%2);
    }
getchar();
    return 0;
}

output
---------


0
10
010
1010



with this try and 2)

 

Thank you virxen so much

I tried the second but I couldn't get the right answer

Code:

#include <stdio.h>

int main(){
	 for (int i=0;i<4;i++){
        printf("\n");
		  for (int j=0;j<(i+1);j++)
				printf("%d",(i+j+1));
    }
getchar();
	 return 0;
}

and I got the output as

1
23
345
567

instead of getting

1
23
345
6789

can anyone help me to correct my answer

 

sorry this is the code

Code:

#include <stdio.h>

int main(){
	 for (int i=0;i<4;i++){
		  printf("\n");
		  for (int j=0;j<(i+1);j++)
				printf("%d",(i+j));
	 }
getchar();
	 return 0;
}

and the output was
0
12
234
3456


instead of getting

0
12
345
6789


what's wrong in the code so I can get the right answer

 

Your code displays on each line values from i (which increases by 1 each new line) to i+j. But you want each line to begin with the last number displayed, plus one.

So how about a counter that just increases each time you print something? Then print the counter instead of trying to calculate something from i and j.

 

Because you tried to code i will give you the answer for a,b.

Code:

#include <stdio.h>

int main(){
    for (int i=0;i<4;i++){
        printf("\n");
        for (int j=0;j<(i+1);j++)
            printf("%d",(i+j+1)%2);
    }
getchar();
int count=0;
    for (int i=0;i<4;i++){
        printf("\n");
        for (int j=0;j<(i+1);j++)
            printf("%d",count++);
    }
getchar();
    return 0;
}