Hi all ,This Is kim00000 I just need help with this: I made a Programme which make a Batch (.bat) File ,which has some commands , So i want the Programme to run that (.bat) file after creating it ,but without defining the batch-file's directory ,cause it'll create it at the same path that the programme is in , Example: Open("Temp.bat"); ,,, Kim00000
You can do that this way : Code: system("Temp.bat"); In case, you need to provide full path to the bat file, remember to use double backslashes (\\) instead of a single one (\) in the path. For example : Code: system("C:\\Temp\\Temp.bat");
But i don't want to define the Path ,i mean that i need a code that opens that file at the same path of the programme. Example:The programme is in that path C:\\CPP\\CPP.exe in my computer ,but if i ran it on another computer of course it won't be at the same path as my computer's ,so the system will not find the file C:\\CPP\\Temp.bat given that the Temp.bat is in another location. got it?
Sorry for the double Replies ,but i won't to explain in more simple way 1)The Programme is running. 2)Temp.bat has been made at the same path as the programme's one. :p the third one is that i need ,if the path i've provided is C:\\Temp.bat ,and i moved the programme to D:\\ ,the (.bat) file will be created in D:\\ ,so no Temp.bat well be found at C:\\ simply: system("%CPP.exe path%~~\\Temp.bat"); GOT IT? :cuss:
